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.已知数列{an}是首项为a1=4,公比为q的等比数列,设bn+2-3log1/4^an(n属于正实数)数列{cn}满足cn=an

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解决时间 2021-11-08 23:13
1.求证{bn}是等差数列:
2若cn≤1、4m^2+m-1对一切正整数n恒成立,求实数m的取值范围。
最佳答案
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全部回答
解:(1)由题意,可得 an=(1/4)^n; 那么: bn+2=3*log(1/4)an=3n; 所以: bn=3n-2,为等差数列; (2)由条件cn= an*bn得到: cn= (1/4)^n*(3n-2)=3n*(1/4)^n-2*(1/4)^n 记cn的前n项和为sn;那么: sn=3[1/4+2*(1/4)^2+……+n*(1/4)^n]-2*(1/4+(1/4)^2+……+(1/4)^n); 记pn=1/4+2*(1/4)^2+……+n*(1/4)^n; --------(1) 则有: 1/4*pn=(1/4)^2+2*(1/4)^3+……+n*(1/4)^(n+1); ------(2) (1)-(2)得到: 3/4 pn=1/4+(1/4)^2+(1/4)^3+……+(1/4)^n-n*(1/4)^(n+1) = 1/3*(1-(1/4)^n)- n*(1/4)^珐辅粹恍诔喝达桶惮垃(n+1) 所以sn可变形为: sn=3[1/3*(1-(1/4)^n)- n*(1/4)^(n+1)]-2*[1/3*(1-(1/4)^n)] =1/3*[1-(1/4)^n]-3n*(1/4)^(n+1); 【说明】在求sn的时候,用的方法是错位相减法,我记得教材里边在求等比数列和的时候用的就是这种方法;
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