matlab的nlinfit问题

a=[1,1,1];
>> r=15:49;
>> b1=[ 0.000010000 0.000160000 0.000840000 0.002390000 0.004150000 0.010370000 0.019870000 0.028860000 0.044920000 0.055200000 0.054620000 0.059010000 0.059650000 0.068670000 0.055330000 0.040070000 0.032520000 0.025670000 0.018140000 0.014650000 0.011940000 0.009660000 0.008380000 0.006950000 0.005590000 0.005320000 0.004050000 0.004600000 0.003400000 0.003210000 0.003420000 0.002950000 0.003690000 0.003750000 0.002660000 ];
>> fun=inline('1/sqrt(2*pi*a(2).^2)*exp(-1/2*(log(r-15)-a(1)).^2/a(2)^2)*a(3)','r','a');
>> ae=nlinfit(t,c,f,a);

程序显示错误：??? Error using ==> nlinfit at 127
MODELFUN should return a vector of fitted values the same length as Y.

然后我简化方程fun=inline('exp(log(r))','r','a')，，还是那个错，，很急大家帮帮忙
r，b1都是35个

我的matlab告诉我这错。
MODELFUN must be a function that returns a vector of fitted values the same size as Y (1-by-35). The model function you
provided returned a result that was 1-by-3.
One common reason for a size mismatch is using matrix operators (*, /, ^) in your function instead of the corresponding
elementwise operators (.*, ./, .^).

如果你还不知道自己哪错了，就试试用fun=inline('exp(log(r))','a','r')再算一下（注意我给你的函数和你写的是不一样的）然后应该就知道了。

%[1 1 1]就是给a(1),a(2),a(3) 参数赋予初值 %程序运行不了是因为你定义的内联函数inline有错，注意t为数组运算符得用点 t=[1790:10:2000]; p=[3.9 5.3 7.2 9.6 12.9 17.1 23.2 31.4 38.6 50.2 62.9 76.0 92.0 106.5 123.2 131.7 150.7 179.3 204.0 226.5 251.4 281.4]; ft=inline('a(1).*a(2)./(a(1)+exp(-a(3).*t).*a(2)-exp(-a(3).*t).*a(1))','a','t'); a=nlinfit(t,p,ft,[1 1 1]) %a = 1.0000 94.7727 1.0000 %但是给出警告，拟合结果不好，得参考帮助设置一下optimset 另外,团idc网上有许多产品团购,便宜有口碑