1.21乘以a=3.49乘以b=99612 a和b 分别是多少 必须是整数

1.21乘以a=3.49乘以b=99612 a和b 分别是多少 必须是整数

1.21乘以a=99612 a=99612/1.21=82323.966942148760330578512396694......
3.49乘以b=99612 b=99612/3.49=28542.120343839541547277936962751......
a和b不可能是整数。
1.21乘以a+3.49乘以b=99612
121a+349b=9961200，a=(9961200-349b)/121=82323-2b+(117-107b)/121，令(117-107b)/121=c则a=82323-2b+c
121c=117-107b，b=(117-121c)/107=1-c+(10-14c)/107，令(10-14c)/107=d则b=1-c+d
107d=10-14c，c=(10-107d)/14=(10-9d)/14-7d，令(10-9d)/14=e则c=e-7d
14e=10-9d，d=(10-14e)/9=1-e+(1-5e)/9，令(1-5e)/9=f则d=1-e+f
9f=1-5e，e=(1-9f)/5=(1-4f)/5-f，令(1-4f)/5=g则e=g-f
5g=1-4f，f=(1-5g)/4=(1-g)/4-g，令(1-g)/4=h则f=h-g
4h=1-g，g=1-4h
f=h-g=h-(1-4h)=h-1+4h=5h-1
e=g-f=1-4h-(5h-1)=1-4h-5h+1=2-9h
d=1-e+f=1-(2-9h)+5h-1=1-2+9h+5h-1=14h-2
c=e-7d=2-9h-7(14h-2)=2-9h-98h+14=16-107h
b=1-c+d=1-(16-107h)+14h-2=1-16+107h+14h-2=121h-17
a=82323-2b+c=82323-2(121h-17)+16-107h=82323-242h+34+16-107h=82373-349h
即就是整数，也有无限多组。下面只是所有的正整数解：
a>0即82373-349h>0，h<82373/349≈236.0258
b>0即121h-17>0，h>17/121≈0.1405
h a b
1,82024,104,2,81675,225,3,81326,346,4,80977,467,5,80628,588,6,80279,709,7,79930,830,8,79581,951,9,79232,1072,10,78883,......,1193,226,3499,27329,227,3150,27450,228,2801,27571,229,2452,27692,230,2103,27813,231,1754,27934,232,1405,28055,233,1056,28176,234,707,28297,235,358,28418,236,9,28539,