植物油能使溴水褪色实验步骤
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解决时间 2021-02-10 02:15
- 提问者网友:雨不眠的下
- 2021-02-09 10:45
植物油能使溴水褪色实验步骤
最佳答案
- 五星知识达人网友:白昼之月
- 2021-02-09 12:00
乙酸,也叫醋酸、冰醋酸,化学式CH3COOH,是一种有机一元酸,为食醋内酸味及刺激性气味的来源。纯的无水乙酸(冰醋酸)是无色的吸湿性液体,凝固点为16.7℃(62℉),凝固后为无色晶体。尽管根据乙酸在水溶液中的解离能力它是一种弱酸,但是乙酸是具有腐蚀性的,其蒸汽对眼和鼻有刺激性作用。乙酸的化学性质:乙酸在水溶液中是一元弱酸,酸度系数为4.8,pKa=4.75(25℃),浓度为1mol/L的醋酸溶液(类似于家用醋的浓度)的pH为2.4,也就是说仅有0.4%的醋酸分子是解离的。
乙酸酸性的体现:CH3COOH<==>CH3COO- + H+
1、与指示剂作用:可使紫色石蕊试液变为红色,使甲基橙变为红色。
2、与碱反应:CH3COOH + NaOH = CH3COONa + H2O
2CH3COOH + Cu(OH)2=Cu(CH3COO)2 + 2H2O
3、与某些活泼金属反应:Mg + 2CH3COOH = Mg(CH3COO)2 + H2↑
Zn + 2CH3COOH = Zn(CH3COO)2 + H2↑
Fe + 2CH3COOH = Fe(CH3COO)2 + H2↑
4、与某些氧化物反应:CaO + 2CH3COOH = (CH3COO)2Ca + H2O
MgO + 2CH3COOH = Mg(CH3COO)2 + H2O
PbO + 2CH3COOH = Pb(CH3COO)2 + H2O
5、与某些弱酸盐反应:2CH3COOH + Na2CO3 =2CH3COONa + CO2 ↑+ H2O
2CH3COOH + Na2S = 2CH3COONa + H2S↑
2CH3COOH + Na2SiO3 =2CH3COONa + H2SiO3↓
CH3COOH + C6H5ONa =C6H5OH (苯酚)+ CH3COONa
乙酸酸性的体现:CH3COOH<==>CH3COO- + H+
1、与指示剂作用:可使紫色石蕊试液变为红色,使甲基橙变为红色。
2、与碱反应:CH3COOH + NaOH = CH3COONa + H2O
2CH3COOH + Cu(OH)2=Cu(CH3COO)2 + 2H2O
3、与某些活泼金属反应:Mg + 2CH3COOH = Mg(CH3COO)2 + H2↑
Zn + 2CH3COOH = Zn(CH3COO)2 + H2↑
Fe + 2CH3COOH = Fe(CH3COO)2 + H2↑
4、与某些氧化物反应:CaO + 2CH3COOH = (CH3COO)2Ca + H2O
MgO + 2CH3COOH = Mg(CH3COO)2 + H2O
PbO + 2CH3COOH = Pb(CH3COO)2 + H2O
5、与某些弱酸盐反应:2CH3COOH + Na2CO3 =2CH3COONa + CO2 ↑+ H2O
2CH3COOH + Na2S = 2CH3COONa + H2S↑
2CH3COOH + Na2SiO3 =2CH3COONa + H2SiO3↓
CH3COOH + C6H5ONa =C6H5OH (苯酚)+ CH3COONa
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