在已打开的Excel中，在Sheet3中打开指定文件(用VBA)

strpath = Application.GetOpenFilename("ACCESS文件(*.mdb), *.mdb")

Application.Workbooks.Open (strpath)

如上语句，条开*.mdb文件后，会打开另外一个Excel文件，
求：怎样更改上边语句，使它不打开另外一个Excel文件，而从当前Excel表的Sheet3表单中打开*.mdb文件内容？

Application.ScreenUpdating = False
Dim sh As Workbook
Filename = Application.GetOpenFilename(FileFilter:="Access 数据库文件 (*.mdb),*.mdb", Title:="请选择文件")
If Filename <> False Then
If Dir(Filename) <> ThisWorkbook.Name Then
Set sh = Workbooks.Open(Filename)
'取生成新表的表单名,start
t = Filename
a = Len(t)
t1 = Left(t, a - 4)
a1 = a - 4
For m = 1 To a - 4
b = Mid(t1, a1, 1)
If b = "\\" Then
Exit For
End If
a1 = a - 4 - m
Next
C = Right(t1, m - 1)
'取生成新表的表单名，end

sh.Sheets(C).Cells.Copy ThisWorkbook.Sheets("sheet3").Range("a1")
sh.Close SAVECHANGES:=False
End If
End If
Application.ScreenUpdating = True

以上语句全部复制，执行

两种方法: 1.你确定读取数据库表名后,将sheet3激活,然后从a1开始黏贴 这个用到ado连接数据库. 2.你新开了workbook,把这张新开的activesheet用move移动到,旧的workbook,改名sheet3也可以. 两种你参考着用吧. 如果你是写vba来开启.那么我建议你用第一种: 写法如下: dim cnn as new adodb.connection dim rs as new adodb.recordset dim cnnstr as string dim sql as string dim icols, i as integer dim datestart, dateend as date cnnstr = "dbq=" & strpath & ";defaultdir=" & 这里写mdb文件的路径 & ";driver={microsoft access driver (*.mdb, *.accdb)};driverid=25;fil=ms access;maxbuffersize=2048;maxscanrows=8;pagetimeout=5;safetransactions=0;threads=3;usercommitsync=yes;" cnn.open cnnstr sheets("sheet3").activate '这句要在你的表有"sheet3"才能使用成功 sqlstr = "selet * from 表名" cnn.commandtimeout = 0 rs.open sqlstr, cnn, 1, 3, adcmdtext for icols = 0 to rs.fields.count - 1 cells(1, icols + 1) = rs.fields(icols).name next '这个循环读取列 [a2].copyfromrecordset rs '放到a2单元格开始插入 rs.close cnn.close set rs = nothing set cnn = nothing