求一款android平台上的doc、docx阅读软件
答案:3 悬赏:80 手机版
解决时间 2021-03-19 02:32
- 提问者网友：爱唱彩虹
- 2021-03-18 09:52
不需要编辑，能阅读就行，最好能修改字体。wps除外。
最佳答案
- 五星知识达人网友：酒者煙囻
- 2021-03-18 11:11
目前就WPS好用，其他的都不行，是因为WPS占内存太多吧。你在网上找找金软office，最好能找到无广告的
全部回答
- 1楼网友：一秋
- 2021-03-18 12:27
解析doc，要tm-extractors-0.4.jar这个包解析xls，要jxl.jar这个包
解析xls
解析docx
01 public static string readdocx(string path) {
02 string river = "";
03 try {
04 zipfile xlsxfile = new zipfile(new file(path));
05 zipentry sharedstringxml = xlsxfile.getentry("word/document.xml");
06 inputstream inputstream = xlsxfile.getinputstream(sharedstringxml);
07 xmlpullparser xmlparser = xml.newpullparser();
08 xmlparser.setinput(inputstream, "utf-8");
09 int evttype = xmlparser.geteventtype();
10 while (evttype != xmlpullparser.end_document) {
11 switch (evttype) {
12 case xmlpullparser.start_tag:
13 string tag = xmlparser.getname();
14 system.out.println(tag);
15 if (tag.equalsignorecase("t")) {
16 river += xmlparser.nexttext() + "\n";
17 }
18 break;
19 case xmlpullparser.end_tag:
20 break;
21 default:
22 break;
23 }
24 evttype = xmlparser.next();
25 }
26 } catch (zipexception e) {
27 e.printstacktrace();
28 } catch (ioexception e) {
29 e.printstacktrace();
30 } catch (xmlpullparserexception e) {
31 e.printstacktrace();
32 }
33 if (river == null) {
34 river = "解析文件出现问题";
35 }
36
37 return river;
38 }
解析xlsx
01 public static string readxlsx(string path) {
02 string str = "";
03 string v = null;
04 boolean flat = false;
05 list ls = new arraylist();
06 try {
07 zipfile xlsxfile = new zipfile(new file(path));
08 zipentry sharedstringxml = xlsxfile
09 .getentry("xl/sharedstrings.xml");
10 inputstream inputstream = xlsxfile.getinputstream(sharedstringxml);
11 xmlpullparser xmlparser = xml.newpullparser();
12 xmlparser.setinput(inputstream, "utf-8");
13 int evttype = xmlparser.geteventtype();
14 while (evttype != xmlpullparser.end_document) {
15 switch (evttype) {
16 case xmlpullparser.start_tag:
17 string tag = xmlparser.getname();
18 if (tag.equalsignorecase("t")) {
19 ls.add(xmlparser.nexttext());
20 }
21 break;
22 case xmlpullparser.end_tag:
23 break;
24 default:
25 break;
26 }
27 evttype = xmlparser.next();
28 }
29 zipentry sheetxml = xlsxfile.getentry("xl/worksheets/sheet1.xml");
30 inputstream inputstreamsheet = xlsxfile.getinputstream(sheetxml);
31 xmlpullparser xmlparsersheet = xml.newpullparser();
32 xmlparsersheet.setinput(inputstreamsheet, "utf-8");
33 int evttypesheet = xmlparsersheet.geteventtype();
34 while (evttypesheet != xmlpullparser.end_document) {
35 switch (evttypesheet) {
36 case xmlpullparser.start_tag:
37 string tag = xmlparsersheet.getname();
38 if (tag.equalsignorecase("row")) {
39 } else if (tag.equalsignorecase("c")) {
40 string t = xmlparsersheet.getattributevalue(null, "t");
41 if (t != null) {
42 flat = true;
43 system.out.println(flat + "有");
44 } else {
45 system.out.println(flat + "没有");
46 flat = false;
47 }
48 } else if (tag.equalsignorecase("v")) {
49 v = xmlparsersheet.nexttext();
50 if (v != null) {
51 if (flat) {
52 str += ls.get(integer.parseint(v)) + " ";
53 } else {
54 str += v + " ";
55 }
56 }
57 }
58 break;
59 case xmlpullparser.end_tag:
60 if (xmlparsersheet.getname().equalsignorecase("row")
61 && v != null) {
62 str += "\n";
63 }
64 break;
65 }
66 evttypesheet = xmlparsersheet.next();
67 }
68 system.out.println(str);
69 } catch (zipexception e) {
70 e.printstacktrace();
71 } catch (ioexception e) {
72 e.printstacktrace();
73 } catch (xmlpullparserexception e) {
74 e.printstacktrace();
75 }
76 if (str == null) {
77 str = "解析文件出现问题";
78 }
79
80 return str;
81 }
- 2楼网友：不如潦草
- 2021-03-18 11:55
openoffice
libreoffice（开源的）
Documents to go
我要举报
如以上问答信息为低俗、色情、不良、暴力、侵权、涉及违法等信息，可以点下面链接进行举报！
大家都在看
推荐资讯