12x-10/4x-3 + 32x-34/8x-9 = 24x-23/8x-7 + 16x-19/4x-5
答案:1 悬赏:30 手机版
解决时间 2021-02-05 06:21
- 提问者网友：ミ烙印ゝ
- 2021-02-04 16:07
12x-10/4x-3 + 32x-34/8x-9 = 24x-23/8x-7 + 16x-19/4x-5
最佳答案
- 五星知识达人网友：玩家
- 2021-02-04 17:10
这种表达方式，容易导致【歧义】，以后可以多加括号的。
(12x-10)/(4x-3)+(32x-34)/(8x-9)=(24x-23)/(8x-7)+(16x-19)/(4x-5)
3-1/(4x-3)+4+2/(8x-9)=3-2/(8x-7)+4+1/(4x-5)
2/(8x-9)-1/(4x-3)=1/(4x-5)-2/(8x-7)
2/(8x-9)+2/(8x-7)=1/(4x-5)+1/(4x-3)
2*16(x-1)/(8x-9)*1//(8x-7)=8(x-1)/(4x-5)*1/(4x-3)
x=1
4/(8x-9)*1/(8x-7)=1/(4x-5)*1/(4x-3)
4(4x-5)(4x-3)-(8x-9)(8x-7)=0
方程无解
最终结论 x=1
(12x-10)/(4x-3)+(32x-34)/(8x-9)=(24x-23)/(8x-7)+(16x-19)/(4x-5)
3-1/(4x-3)+4+2/(8x-9)=3-2/(8x-7)+4+1/(4x-5)
2/(8x-9)-1/(4x-3)=1/(4x-5)-2/(8x-7)
2/(8x-9)+2/(8x-7)=1/(4x-5)+1/(4x-3)
2*16(x-1)/(8x-9)*1//(8x-7)=8(x-1)/(4x-5)*1/(4x-3)
x=1
4/(8x-9)*1/(8x-7)=1/(4x-5)*1/(4x-3)
4(4x-5)(4x-3)-(8x-9)(8x-7)=0
方程无解
最终结论 x=1
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