用c++编写一个程序

要求输入如“sfasdf123”字符串类型，输出转化为123 int型的

当输入abc123def456时. 输出123<回车>456<回车>;

代码如下:

#include <stdio.h>

int main()
{
char in[20],c;
int bit=0,out=0;

while(c=getchar(),c!='\n'){
if(c>='0'&&c<='9')
{
if(bit){
out*=10;
out+=c-'0';
}
else
{
bit=1;
out+=c-'0';
}
}
else{
if(bit)
{
printf("%d\n",out);
bit=0;
out=0;
}
}
}
if(bit)
printf("%d\n",out);
return 0;
}
附图:

#include <iostream> #include <string> #include <vector> #include <boost/regex.hpp> #include <boost/lexical_cast.hpp> #include <boost/lambda/lambda.hpp> using namespace std; using namespace boost; int main() { regex r( "\\d+" ); string s = "asfsdf123sadgsd333"; boost::sregex_iterator it( s.begin(), s.end(), r ), end; vector<int> v; while ( it != end ) { v.push_back( lexical_cast<int>( *it++ ) ); } for_each( v.begin(), v.end(), cout << lambda::_1 << ' ' ); cin.get(); }

#include <stdio.h> #include <stdlib.h>

void GetNum(char* s, char* d) { while (*s < '0' || *s > '9') s++; while (*s >= '0' && *s <= '9') *d++ = *s++; *d = 0; } int main() { char s[] = "sfasdf123"; char num[100];

GetNum(s, num); printf("%d\n", atoi(num)); return 0; }