计算：x-x^2/（-x-3x-2）-x^2+1/x^2+3x+2
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解决时间 2021-11-17 10:20
- 提问者网友：送舟行
- 2021-11-16 16:46
计算：x-x^2/（-x-3x-2）-x^2+1/x^2+3x+2
最佳答案
- 五星知识达人网友：孤独入客枕
- 2021-11-16 17:04
(x-x^2)/（-x^2-3x-2）-(x^2+1)/(x^2+3x+2)
=(x²-x)/(x²+3x+2)-(x²+1)/(x²+3x+2)
=(x²-x-x²-1)/(x+1)(x+2)
=-(x+1)/(x+1)(x+2)
=-1/(x+2)
(3x+1)/(x^2-5x-6)+(2x+5)/(6+5x-x^2)-(x-8)/(x^2-5x-6)
=(3x+1)/(x²-5x-6)-(2x+5)/(x²-5x-6)-(x-8)/(x²-5x-6)
=(3x+1-2x-5-x+8)/(x²-5x-6)
=4/(x²-5x-6)
=(x²-x)/(x²+3x+2)-(x²+1)/(x²+3x+2)
=(x²-x-x²-1)/(x+1)(x+2)
=-(x+1)/(x+1)(x+2)
=-1/(x+2)
(3x+1)/(x^2-5x-6)+(2x+5)/(6+5x-x^2)-(x-8)/(x^2-5x-6)
=(3x+1)/(x²-5x-6)-(2x+5)/(x²-5x-6)-(x-8)/(x²-5x-6)
=(3x+1-2x-5-x+8)/(x²-5x-6)
=4/(x²-5x-6)
全部回答
- 1楼网友：山河有幸埋战骨
- 2021-11-16 18:09
不会
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