分式的加减：(x-3/x²+6x+9)+(x/9-x²)
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解决时间 2021-02-25 12:16
- 提问者网友：酱爆肉
- 2021-02-24 19:06
分式的加减：(x-3/x²+6x+9)+(x/9-x²)
最佳答案
- 五星知识达人网友：骨子里都是戏
- 2021-02-24 20:43
(x-3)／(x+3)^2+x／(3+x)(3-x)
=[(x-3)^2-x(x+3)]／(x+3)^2(x-3)
=(x^2-6x+9-x^2-3x)／(x+3)^2(x-3)
=(-9x+9)／(x+3)^2(x-3)
=9(1-x)／(x+3)^2(x-3)
=[(x-3)^2-x(x+3)]／(x+3)^2(x-3)
=(x^2-6x+9-x^2-3x)／(x+3)^2(x-3)
=(-9x+9)／(x+3)^2(x-3)
=9(1-x)／(x+3)^2(x-3)
全部回答
- 1楼网友：逐風
- 2021-02-24 21:12
原式=(x-3)/(x+3)²-x/(x+3)(x-3)
=[(x-3)²-x(x+3)]/(x+3)²(x-3)
=(x²-6x+9-x²-3x)/(x+3)²(x-3)
=(x²-6x+9-x²-3x)/(x+3)²(x-3)
=(9-9x)/(x+3)²(x-3)
=[(x-3)²-x(x+3)]/(x+3)²(x-3)
=(x²-6x+9-x²-3x)/(x+3)²(x-3)
=(x²-6x+9-x²-3x)/(x+3)²(x-3)
=(9-9x)/(x+3)²(x-3)
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