c语言 求解

c语言 求解

#include
#include
int main()
{
int startTimeOf0am=0,startTimeOf8am=8*60,startTimeOf6pm=18*60,startTimeOf24pm=24*60;
int startTime,durationTime,dayOfWeek;
int duration,endTime;
float cost=0;

while(1)
{
printf("Enter the start time, duration and day of the week:(-1 to exit)");
scanf("%d %d %d",&startTime,&durationTime,&dayOfWeek);
if(startTime<0||startTime>=24*60||durationTime<0||dayOfWeek<0||dayOfWeek>7)
{
printf("Illegal input\n");
if(startTime==-1)
{
return 0;
}
}

while(durationTime>0)
{
endTime=startTime+durationTime;
if(dayOfWeek>=1&&dayOfWeek<=5)
{
if(startTime {
if(endTime>=startTimeOf8am)
{
duration=startTimeOf8am-startTime;
durationTime-=duration;
startTime=startTimeOf8am;
}
else
{
duration=durationTime;
durationTime=0;
}
cost+=duration*0.25;
}
else if(startTime>=startTimeOf8am&&startTime {
if(endTime>=startTimeOf6pm)
{
duration=startTimeOf6pm-startTime;
durationTime-=duration;
startTime=startTimeOf6pm;
}
else
{
duration=durationTime;
durationTime=0;
}
cost+=duration*0.4;
}
else
{
if(endTime>=startTimeOf24pm)
{
duration=startTimeOf24pm-startTime;
durationTime-=duration;
startTime=startTimeOf0am;
dayOfWeek++;
if(dayOfWeek>7) dayOfWeek=1;
}
else
{
duration=durationTime;
durationTime=0;
}
cost+=duration*0.25;
}
}
else if(dayOfWeek==6||dayOfWeek==7)
{
if(endTime>=startTimeOf24pm)
{
duration=startTimeOf24pm-startTime;
durationTime-=duration;
startTime=startTimeOf0am;
dayOfWeek++;
if(dayOfWeek>7) dayOfWeek=1;
}
else
{
duration=durationTime;
durationTime=0;
}
cost+=duration*0.15;
}
}

printf("The cost of the call is:%.2f\n",cost);
}

//system("pause");
return 0;
}

输入 542 12 3 输出4.80
输入 0 1440 1 输出450.00
输入 0 1440 6 输出216.00
输入 0 2880 5 输出666.00

支持跨8点，跨6点，跨天的持续电话时间。追问绝对霸气啊

。。。。。直接要的一个计费软件追问看不懂4.8是怎么算出来的追答看说明，542就是通话开始时间，根据说明这个时间是从夜间12点算，上午9:02就是542，12是通话时长，3是通话日期，根据说明3代表星期三，星期三8:00am到6:00pm的通话费是每分钟0.4，12分钟就是4.8