如何生成一个随机的字符串
答案:1 悬赏:40 手机版
解决时间 2021-01-30 08:44
- 提问者网友:未信
- 2021-01-29 11:45
如何生成一个随机的字符串
最佳答案
- 五星知识达人网友:低血压的长颈鹿
- 2021-01-29 13:08
private static Random randGen = null;
private static char[] numbersAndLetters = null;
public static final String randomString(int length) {
if (length < 1) {
return null;
}
if (randGen == null) {
randGen = new Random();
numbersAndLetters = ("0123456789abcdefghijklmnopqrstuvwxyz" +
"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ").toCharArray();
//numbersAndLetters = ("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ").toCharArray();
}
char [] randBuffer = new char[length];
for (int i=0; i randBuffer[i] = numbersAndLetters[randGen.nextInt(71)];
//randBuffer[i] = numbersAndLetters[randGen.nextInt(35)];
}
return new String(randBuffer);
}
//调用此方法randomString(int),int是字符串的长度,即可产生指定长度的随机字符串。
private static char[] numbersAndLetters = null;
public static final String randomString(int length) {
if (length < 1) {
return null;
}
if (randGen == null) {
randGen = new Random();
numbersAndLetters = ("0123456789abcdefghijklmnopqrstuvwxyz" +
"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ").toCharArray();
//numbersAndLetters = ("0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ").toCharArray();
}
char [] randBuffer = new char[length];
for (int i=0; i
//randBuffer[i] = numbersAndLetters[randGen.nextInt(35)];
}
return new String(randBuffer);
}
//调用此方法randomString(int),int是字符串的长度,即可产生指定长度的随机字符串。
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