会计算机c语言的帮帮忙

求方程a*2+bx+c=0的根，用3个函数分别求当b2-4ac大于0
、等于0和小于0时的根并输出结果，从主函数输入a、b、c的值

#include<stdio.h>
#include<conio.h>
#include<math.h>
main()
{
int a,b ,c;
float x1,x2;
clrscr();
printf("enter the a,b&c ");
scanf("%d%d%d",&a,&b,&c);
if(b*b-4*a*c>=0)
{
x1=(-b+sqrt(b*b-4*a*c))/(2*a);
x2=(-b-sqrt(b*b-4*a*c))/(2*a);
printf("the first answer is %f,the second answer is %f",x1,x2);
}
else
printf("no answer");
getch();
}