python求变化率
答案:2 悬赏:50 手机版
解决时间 2021-11-07 18:21
- 提问者网友：wodetian
- 2021-11-07 00:33
python求变化率
最佳答案
- 五星知识达人网友：枭雄戏美人
- 2021-11-07 02:07
d = [3000,3050,2000,2400,3000,1000,4000]
r = []
for i in range(len(d)-1):
r.append(float(d[i]-d[i+1])/float(d[i]))
print r
r = []
for i in range(len(d)-1):
r.append(float(d[i]-d[i+1])/float(d[i]))
print r
全部回答
- 1楼网友：逐風
- 2021-11-07 02:41
>>> data = [3000,3050,2000,2400,3000,1000,4000]
>>> result = []
>>> it = iter(data)
>>> n1 = float(it.next())
>>> for n2 in it:
result.append((n2-n1)/n1)
n1 = float(n2)
>>> result
[0.016666666666666666, -0.3442622950819672, 0.2, 0.25, -0.6666666666666666, 3.0]
>>>
>>> result = []
>>> it = iter(data)
>>> n1 = float(it.next())
>>> for n2 in it:
result.append((n2-n1)/n1)
n1 = float(n2)
>>> result
[0.016666666666666666, -0.3442622950819672, 0.2, 0.25, -0.6666666666666666, 3.0]
>>>
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