(1+0.1)+(2+0.1*2)+(3+0.1*3)+...+(99+0.1*99)+(100+0.1*100)
答案:5 悬赏:20 手机版
解决时间 2021-12-17 16:18
- 提问者网友:无处安放的痛
- 2021-12-16 23:01
(1+0.1)+(2+0.1*2)+(3+0.1*3)+...+(99+0.1*99)+(100+0.1*100)
最佳答案
- 五星知识达人网友:萝莉收纳盒
- 2021-12-16 23:06
(1+0.1)+(2+0.1*2)+(3+0.1*3)+...+(99+0.1*99)+(100+0.1*100)
=(1+2+3+……+99+100)+0.1*(1+2+3+……+99+100)
=(1+100)*100/2+0.1*(1+100)*100/2
=5050+505
=5555
=(1+2+3+……+99+100)+0.1*(1+2+3+……+99+100)
=(1+100)*100/2+0.1*(1+100)*100/2
=5050+505
=5555
全部回答
- 1楼网友:彼岸雨露
- 2021-12-17 03:35
(1+0.1)+(2+0.1*2)+(3+0.1*3)+.............+(99+0.1*99)+(100+0.1*99)
=1.1*(1+2+3+……+99+100)
=1.1*(1+100)*100/2
=55*101
=5555
- 2楼网友:我与学霸最萌分数差
- 2021-12-17 02:50
(1+0.1)+(2+0.1*2)+(3+0.1*3)+...+(99+0.1*99)+(100+0.1*100)
=(1+2+3+……+100)+0.1×(1+2+3+……+100)
=5050+ 0.1×5050
=5050+505
=5555
- 3楼网友:沵留给涐得记忆
- 2021-12-17 01:33
原式=(1+2+3+......+100)+0.1(1+2+3+......+100)=1.1(1+2+3+......+100)=1.1*5050=5555
- 4楼网友:尘沙飞扬
- 2021-12-16 23:55
(1+2.1)+(2+2.1*2)+(3+2.1*3)+.......+(99+2.1*99)+(100+2.1*100)
=(1+2+......+100)+2.1(1+2+3+......100)
=(1+100)*100/2+2.1*5050
=15655
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