C语言编写的收银台结算程序。

设计要求：根据货品的输入代码，统计货品价格，并打印清单，能有找零功能。
如果有资源谢谢分享一下。1204935800

//以下是参考代码有相似结构，数据结构自己设计一下。
//如果没参考价值，手下留情，别点不采纳。

#define MAXPARKINGPOS 100
#define MAXPRICETYPE 3
#define MAXLINE 4096

struct detail
{
char num[MAXLINE];
char name[MAXLINE];
double pricePerHour;
time_t start;
time_t end;
double period;
double cost;
};

static int currentParkingNum = 0;
static struct detail detailBuf[MAXPARKINGPOS];
static double priceBuf[MAXPRICETYPE] = {11.0,22.0,33.0};

int main(void) {
char buf[MAXLINE];
struct detail *myParking;
int iChoice,leavingIndex,i,numEexisted;
struct tm *begin,*end;

while(true) {
selectService:
printf("Service type,what is your choice?\n1.park\n2.leave\n3.exit\n");
gets(buf);

if(strcmp(buf,"3") == 0) {
return 0;
}

if(strcmp(buf,"1") == 0) {
//park
if(currentParkingNum == MAXPARKINGPOS) {
printf("Sorry,not empty!\n\n");
continue;
}

myParking = detailBuf+currentParkingNum;

printf("your name:\n");
gets(myParking->name);

printf("your parking num:\n");
gets(myParking->num);

numEexisted = 0;
for(i=0;i if(strcmp(detailBuf[i].num,myParking->num) == 0) {
numEexisted =1;
break;
}
}

if(numEexisted != 0) {
printf("The car %s is in\n\n",myParking->num);
goto selectService;
}

selectPrice:
printf("Service cost,what is your choice?\n");
for(int i=0;i < MAXPRICETYPE; i++) {
printf("%d.$%.2f per hour\n",i+1,priceBuf[i]);
}
gets(buf);
iChoice = atoi(buf);
if(!(iChoice >= 1 && iChoice <=MAXPRICETYPE)) {
printf("Your choice is incorrect!\n\n");
goto selectPrice;
}
myParking->pricePerHour=priceBuf[iChoice-1];

time(&myParking->start);

currentParkingNum++;

printf("Parcking ok!\n\n");
}else if(strcmp(buf,"2") == 0) {
//leave

printf("your parking num:\n");
gets(buf);

myParking = NULL;
for(i=0;i if(strcmp(detailBuf[i].num,buf) == 0) {
myParking = &detailBuf[i];
leavingIndex = i;
break;
}
}

if(myParking ==NULL) {
printf("Cannot find your car!\n\n");
continue;
}

myParking->end = time(&myParking->end);
myParking->period = difftime(myParking->end,myParking->start);

myParking->cost= myParking->period/3600.0*myParking->pricePerHour;

printf("****** Cost Details ******\n");
printf("name:%s\n",myParking->name);
printf("number:%s\n",myParking->num);
printf("price:%.2f\n",myParking->pricePerHour);

begin = localtime(&myParking->start);
strftime(buf,sizeof(buf),"%Y-%m-%d %H:%M:%S",begin);
printf("begin:%s\n",buf);

end = localtime(&myParking->end);
strftime(buf,sizeof(buf),"%Y-%m-%d %H:%M:%S",end);
printf("end:%s\n",buf);

printf("period:%.2f hour(s)\n",myParking->period/3600.0);

printf("cost:$%.2f\n",myParking->cost);
printf("service:$%.2f per hour\n",myParking->pricePerHour);

for(i = leavingIndex; i < currentParkingNum;i++) {
if(i+1 < currentParkingNum) {
detailBuf[i]=detailBuf[i+1];
}
}

detailBuf[currentParkingNum-1].cost=0.0;
detailBuf[currentParkingNum-1].end=0;
detailBuf[currentParkingNum-1].name[0]='\0';
detailBuf[currentParkingNum-1].num[0]='\0';
detailBuf[currentParkingNum-1].period=0.0;
detailBuf[currentParkingNum-1].pricePerHour=0.0;
detailBuf[currentParkingNum-1].start=0;

currentParkingNum--;

printf("Leaving ok!\n\n");
}else{
printf("Your choice is incorrect!\n\n");
continue;
}
}

return 0;
}

C++的要不要？ C的太麻烦了，除非就实现简单的功能

建立商品库 建立出售库 每刷一毛，查询商品库，记录出售库。。。。。直到结算，开始新一笔。。。。。。。。。。如此循环