已知磷酸的pKa1=2.12,pKa2=7.21,pKa3=12.66,若控制磷酸盐溶液的PH=6.0,则安浓度的大小顺序,
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解决时间 2021-03-26 19:48
- 提问者网友:眉目添风霜
- 2021-03-26 10:41
已知磷酸的pKa1=2.12,pKa2=7.21,pKa3=12.66,若控制磷酸盐溶液的PH=6.0,则安浓度的大小顺序,
最佳答案
- 五星知识达人网友:街头电车
- 2021-03-26 10:55
直接用分布系数计算
H3PO4的分布系数=[H+]^3 /{ [H+]^3 +[H+]^2*Ka1 +[H+]*Ka1 *Ka2 +Ka1*Ka2*Ka3}
=(10^-6)^3 / { (10^-6)^3 +(10^-6)^2 *10^-2.12 +(10^-6)*(10^-2.12)* (10^-7.21 )+ (10^-2.12)* (10^-7.21 )*(10^-12.66)
=1.24*10^-4
H2PO4-的分布系数=[H+]^2*Ka1 /{ [H+]^3 +[H+]^2*Ka1 +[H+]*Ka1 *Ka2 +Ka1*Ka2*Ka3}
=(10^-6)^2 *10^-2.12 / { (10^-6)^3 +(10^-6)^2 *10^-2.12 +(10^-6)*(10^-2.12)* (10^-7.21 )+ (10^-2.12)* (10^-7.21 )*(10^-12.66)
=0.941
HPO42-的分布系数=[H+]*Ka1*Ka2 /{ [H+]^3 +[H+]^2*Ka1 +[H+]*Ka1 *Ka2 +Ka1*Ka2*Ka3}
=(10^-6) *(10^-2.12)* (10^-7.21 ) / { (10^-6)^3 +(10^-6)^2 *10^-2.12 +(10^-6)*(10^-2.12)* (10^-7.21 )+ (10^-2.12)* (10^-7.21 )*(10^-12.66)
=0.058
PO43-的分布系数=Ka1*Ka2*Ka3 /{ [H+]^3 +[H+]^2*Ka1 +[H+]*Ka1 *Ka2 +Ka1*Ka2*Ka3}
=(10^-2.12)* (10^-7.21 ) *(10^-12.66) / { (10^-6)^3 +(10^-6)^2 *10^-2.12 +(10^-6)*(10^-2.12)* (10^-7.21 )+ (10^-2.12)* (10^-7.21 )*(10^-12.66)
=1.27*10^-8
因此 H2PO4- >HPO42- >H3PO4 >PO43-
H3PO4的分布系数=[H+]^3 /{ [H+]^3 +[H+]^2*Ka1 +[H+]*Ka1 *Ka2 +Ka1*Ka2*Ka3}
=(10^-6)^3 / { (10^-6)^3 +(10^-6)^2 *10^-2.12 +(10^-6)*(10^-2.12)* (10^-7.21 )+ (10^-2.12)* (10^-7.21 )*(10^-12.66)
=1.24*10^-4
H2PO4-的分布系数=[H+]^2*Ka1 /{ [H+]^3 +[H+]^2*Ka1 +[H+]*Ka1 *Ka2 +Ka1*Ka2*Ka3}
=(10^-6)^2 *10^-2.12 / { (10^-6)^3 +(10^-6)^2 *10^-2.12 +(10^-6)*(10^-2.12)* (10^-7.21 )+ (10^-2.12)* (10^-7.21 )*(10^-12.66)
=0.941
HPO42-的分布系数=[H+]*Ka1*Ka2 /{ [H+]^3 +[H+]^2*Ka1 +[H+]*Ka1 *Ka2 +Ka1*Ka2*Ka3}
=(10^-6) *(10^-2.12)* (10^-7.21 ) / { (10^-6)^3 +(10^-6)^2 *10^-2.12 +(10^-6)*(10^-2.12)* (10^-7.21 )+ (10^-2.12)* (10^-7.21 )*(10^-12.66)
=0.058
PO43-的分布系数=Ka1*Ka2*Ka3 /{ [H+]^3 +[H+]^2*Ka1 +[H+]*Ka1 *Ka2 +Ka1*Ka2*Ka3}
=(10^-2.12)* (10^-7.21 ) *(10^-12.66) / { (10^-6)^3 +(10^-6)^2 *10^-2.12 +(10^-6)*(10^-2.12)* (10^-7.21 )+ (10^-2.12)* (10^-7.21 )*(10^-12.66)
=1.27*10^-8
因此 H2PO4- >HPO42- >H3PO4 >PO43-
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