回文素数编程

回文素数怎么判断啊？谁能给我代码？提示我一下

#include <stdlib.h>
#include <iostream>
#include <cmath>
using namespace std;

bool isPrime(int num) {
for (int i = 2; i <= sqrt(num); i++) {

if (num % i == 0)
return false;
}
return true;
}
//Create a function that judges if a number is a palindrome
bool isPalindrome(int num) {
int n = 1, chushu = 10;
while (num / chushu != 0) {
chushu *= 10;
n++;
} //Find how large is a number
int division = (int) pow(10.0, n - 1);
//Judge a number if it's length is even
if (n % 2 == 0) {
for (int i = 0; i < n / 2; i++) {
int first = num / division; //Get the first number of the even-length number
int last = num % 10; //Get the last number of the even-lengthnumber
if (first != last) {
return false;
}
num = (int) ((num - first * division) / 10);
division /= 10;
}
return true;
}
//Judge a number if it's length is odd
else {
for (int i = 0; i < (n - 1) / 2; i++) {
int first = num / division;
int last = num % 10;
if (first != last) {
return false;
}
num = ((num - first * division) / 10);
division /= 10;
}
return true;
}
}

int main(int argc, char** argv) {
int Min, Max;
cin >> Min >> Max; //Input to determine the range
for (int num = Min; num <= Max; num++) {
//Call the two functions
if ((isPrime(num)) && (isPalindrome(num))) {
cout << num << endl;
}
num++;
}
return (EXIT_SUCCESS);
}

#include <stdio.h>#include <math.h>int HunWen(int n);int SuShu(int n);int main(int argc, char *argv[]){ int i; for (i = 10; i < 1000; i++) { if (HunWen(i) && SuShu(i)) { printf("%d\t", i); } } return 0;} int HunWen(int n){ int i, t = n, bit = 0; int a[5]; while (t > 0) { a[bit++] = t % 10; t /= 10; } for (i = 0; i < bit/2; i++) { if (a[i] != a[bit-i-1]) { break; } } if (i == bit/2) { return 1; } else { return 0; }} int SuShu(int n){ int i; for (i = 2; i < n; i++) { if (n % i == 0) { break; } } if (i == n) { return 1; } else { return 0; }}