cos(π/32)*cos(π/16)*cos(π/8)=
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解决时间 2021-02-22 11:44
- 提问者网友：相思似海深
- 2021-02-21 22:31
cos(π/32)*cos(π/16)*cos(π/8)=
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- 五星知识达人网友：有你哪都是故乡
- 2021-02-21 22:43
Cos[Pi/32] Cos[Pi/16] Cos[Pi/8] = 1/(Sec[Pi/8] Sec[Pi/16] Sec[Pi/32]) = -((-1)^(25/32) (1 + (-1)^(1/16)) (1 + (-1)^(1/8)) (1 + (-1)^(1/4)))/8
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- 1楼网友：归鹤鸣
- 2021-02-21 23:02
cosπ/17*cos2π/17*cos4π/17*cos8π/17=(sinπ/17cosπ/17*cos2π/17*cos4π/17*cos8π/17)/sinπ/17=(1/2sin2π/17 cos2π/17*cos4π/17*cos8π/17)/sinπ/17 =sin16π/17/16sinπ/17 =1/16
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