若多项式(2mx^2-x^2 5x 8)-(5X^2-3y 5x)的值与x的取值无关,求m^3-(2m^2-(5m-4) m)
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解决时间 2021-01-14 18:14
- 提问者网友:太高姿态
- 2021-01-14 02:53
若多项式(2mx^2-x^2 5x 8)-(5X^2-3y 5x)的值与x的取值无关,求m^3-(2m^2-(5m-4) m)
最佳答案
- 五星知识达人网友:撞了怀
- 2021-01-14 03:58
(2mx^2-x^2 5x 8)-(5X^2-3y 5x)
=2mx^2-x^2+5x+8-5X^2+3y-5x
=(2m-6)x^2+3Y+8,
根据题意:
2m-6=0 , m=3,
m^3-(2m^2-(5m-4) m
=m^3-(2m^2-5m^2+4m)
=m^3+3m^2-4m
=27+27-12
=42.
=2mx^2-x^2+5x+8-5X^2+3y-5x
=(2m-6)x^2+3Y+8,
根据题意:
2m-6=0 , m=3,
m^3-(2m^2-(5m-4) m
=m^3-(2m^2-5m^2+4m)
=m^3+3m^2-4m
=27+27-12
=42.
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