请教一个关于python处理json的问题

请教一个关于python处理json的问题

{
data : {
{
tg_i":" 1080723 ",
contest_i" : "1001",
sid : "1567515287"
},
{
tg_id : "1080723",
contest_id : "1001",
sid : "1567515287"
}
},
total : "2"
}

然后经过修改，变成：
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{"data":{{"tg_i":"1080723","contest_i":"1001","sid":"1567515287"},{"tg_id":"1080723","contest_id":"1001","sid":"1567515287"}},"total":"2"}

格式化为：
?

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{
"data" : { {
"tg_i" : "1080723",
"contest_i" : "1001",
"sid" : "1567515287"
}, {
"tg_id" : "1080723",
"contest_id" : "1001",
"sid" : "1567515287"
}
},
"total" : "2"
}

但是，去用json解析，但是出错：

Python 2.7.3 (default, Apr 10 2012, 23:24:47) [MSC v.1500 64 bit (AMD64)] on win32

Type "copyright", "credits" or "license()" for more information.
>>> import json
>>> json.loads(‘{"data":{{"tg_i":"1080723","contest_i":"1001","sid":"1567515287"},{"tg_id":"1080723","contest_id":"1001","sid":"1567515287"}},"total":"2"}’)
Traceback (most recent call last):

File "", line 1, in
json.loads(‘{"data":{{"tg_i":"1080723","contest_i":"1001","sid":"1567515287"},{"tg_id":"1080723","contest_id":"1001","sid":"1567515287"}},"total":"2"}’)
File "D:\tmp\dev_install_root\Python27_x64\lib\json\__init__.py", line 326, in loads
return _default_decoder.decode(s)
File "D:\tmp\dev_install_root\Python27_x64\lib\json\decoder.py", line 366, in decode
obj, end = self.raw_decode(s, idx=_w(s, 0).end())
File "D:\tmp\dev_install_root\Python27_x64\lib\json\decoder.py", line 382, in raw_decode
obj, end = self.scan_once(s, idx)
ValueError: Expecting property name: line 1 column 9 (char 9)

【折腾过程】
1.刚开始，看了看：
{"data":{{"tg_i":"1080723","contest_i":"1001","sid":"1567515287"},{"tg_id":"1080723","contest_id":"1001","sid":"1567515287"}},"total":"2"}
好像也都是正常的，没什么错误。
2.后来才发现，对应着错误的位置：
column 9
是大括号'{‘
对应着，格式化的结果中的：
"data" : { {
中的第一个大括号
然后才发现，原来是，data键的值，此处写成用大括号括起来的：
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"data" : { {
"tg_i" : "1080723",
"contest_i" : "1001",
"sid" : "1567515287"
}, {
"tg_id" : "1080723",
"contest_id" : "1001",
"sid" : "1567515287"
}
},

但是，实际上，data的值，只是两个dict，所以，应该是：
要么改为list：
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"data" : [{
"tg_i" : "1080723",
"contest_i" : "1001",
"sid" : "1567515287"
}, {
"tg_id" : "1080723",
"contest_id" : "1001",
"sid" : "1567515287"
}
],

要么改为dict：
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"data1" : {
"tg_i" : "1080723",
"contest_i" : "1001",
"sid" : "1567515287"
},
"data2" : {
"tg_id" : "1080723",
"contest_id" : "1001",
"sid" : "1567515287"
},

对应着，非格式化的内容就是：
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{"data":[{"tg_i":"1080723","contest_i":"1001","sid":"1567515287"},{"tg_id":"1080723","contest_id":"1001","sid":"1567515287"}],"total":"2"}

和：
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{"data1":{"tg_i":"1080723","contest_i":"1001","sid":"1567515287"}, "data2":{"tg_id":"1080723","contest_id":"1001","sid":"1567515287"},"total":"2"}

这样才可以正常解析：

>>> json.loads(‘{"data":[{"tg_i":"1080723","contest_i":"1001","sid":"1567515287"},{"tg_id":"1080723","contest_id":"1001","sid":"1567515287"}],"total":"2"}’)

{u’total’: u’2′, u’data’: [{u’sid’: u’1567515287′, u’contest_i’: u’1001′, u’tg_i’: u’1080723′}, {u’tg_id’: u’1080723′, u’contest_id’: u’1001′, u’sid’: u’1567515287′}]}
>>> json.loads(‘{"data1":{"tg_i":"1080723","contest_i":"1001","sid":"1567515287"}, "data2":{"tg_id":"1080723","contest_id":"1001","sid":"1567515287"},"total":"2"}’)
{u’total’: u’2′, u’data1′: {u’sid’: u’1567515287′, u’contest_i’: u’1001′, u’tg_i’: u’1080723′}, u’data2′: {u’tg_id’: u’1080723′, u’contest_id’: u’1001′, u’sid’: u’1567515287′}}

【总结】
折腾json的话，前提要了解json的语法和规则。
其次才是用某种语言去处理json。