若x^3n=2,求2x^2n*x^4n+x^4n*x^5n的值
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解决时间 2021-01-27 01:54
- 提问者网友：太高姿态
- 2021-01-26 00:57
若x^3n=2,求2x^2n*x^4n+x^4n*x^5n的值
最佳答案
- 五星知识达人网友：一叶十三刺
- 2021-01-26 02:14
2x^2n*x^4n+x^4n*x^5n
=2x^(6n)+x^(9n)
=2[x^(3n)]^2+[x^(3n)]^3
=2*4+2^3
=16
=2x^(6n)+x^(9n)
=2[x^(3n)]^2+[x^(3n)]^3
=2*4+2^3
=16
全部回答
- 1楼网友：街头电车
- 2021-01-26 04:17
原式=2x^2n * x^4n+x^4n * x^5n
=x^4n(2x^2n+x^5n)
=x^3n*x^n(2x^2n+x^5n)
=2x^n*x^2n(2x+x3n)
=2x^3n(2x+x^3n)
=4(2x+2)
=8x+8
满意请采纳
- 2楼网友：低血压的长颈鹿
- 2021-01-26 03:05
2x^(2n)*x^(4n)+x^(4n)*x^(5n)
=2x^(6n)+x^(9n)
=2[x^(3n)]^2 +[x^(3n)]^3
=8+8
=16
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