c语言用switch实现输入出生年份,输出属相

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解决时间 2021-03-14 10:39

提问者网友：你挡着我发光了
2021-03-14 00:47

最佳答案

五星知识达人网友：冷風如刀
2021-03-14 02:11

#include
int main()
{
    int year, t;
    scanf ("%d", &year);
    t = year%12;
    switch(t){
    case 0:
        printf ("猴");break;
    case 1:
        printf ("鸡");break;
    case 2:
        printf ("狗");break;
    case 3:
        printf ("猪");break;
    case 4:
        printf ("鼠");break;
    case 5:
        printf ("牛");break;
    case 6:
        printf ("虎");break;
    case 7:
        printf ("兔");break;
    case 8:
        printf ("龙");break;
    case 9:
        printf ("蛇");break;
    case 10:
        printf ("马");break;
    case 11:
        printf ("羊");break;

    }
    return 0;
}

全部回答

1楼网友：雪起风沙痕
2021-03-14 03:54

#include
#include
int main(int argc, char *argv[])
{
int year;

scanf("%d",&year);
year=((int)fabs(year-2008))%12+1;//找到鼠年为基准点，2008年是鼠年
switch(year)
{
case 1: printf("Rat charm, 子鼠\n");break;
case 2: printf("Ox patient, 丑牛\n");break;
case 3: printf("Tiger sensitive, 寅虎\n");break;
case 4: printf("Rabbit articulate, 卯兔\n");break;
case 5: printf("Dragon healthy, 辰龙\n");break;
case 6: printf("Snake deep, 巳蛇\n");break;
case 7: printf("Horse popular, 午马\n");break;
case 8: printf("Goat elegant, 未羊\n");break;
case 9: printf("Monkey clever, 申猴\n");break;
case 10: printf("Rooster deep thinkers, 酉鸡\n");break;
case 11: printf("Dog loyalty, 戌狗\n");break;
case 12: printf("Pig chivalrous. 亥猪\n");break;
default: printf("Error!\n");break;
}
return 0;
}

2楼网友：人類模型
2021-03-14 03:38

简单代码如下：
思路输入年份去对12取余得出余数就可以知道属相。
#include
int main()
{
int year, t;
scanf ("%d", &year);
t = year%12;
switch(t){
case 0:
printf ("猴");break;
case 1:
printf ("鸡");break;
case 2:
printf ("狗");break;
case 3:
printf ("猪");break;
case 4:
printf ("鼠");break;
case 5:
printf ("牛");break;
case 6:
printf ("虎");break;
case 7:
printf ("兔");break;
case 8:
printf ("龙");break;
case 9:
printf ("蛇");break;
case 10:
printf ("马");break;
case 11:
printf ("羊");break;

}
return 0;
}

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