(x2+x+1)(x+2)
(x2-x-1)(x+1)
(x2+2x-1)(x-1)
(x2-2x+3)(x-2)
(a2+3a-2)(a+3)
(a2-3a+4)(a-3)
(a2+4a+1)(2a-1)
(a2-4a+2)(3a+2)
(2x2-3)(x+5)
(x2+x+1)(x+2)(x2-x-1)(x+1)(x2+2x-1)(x-1)(x2-2x+3)(x-2)(a2+3a-2)(a+3)(a2-3a+4)(a-3)(
答案:2 悬赏:60 手机版
解决时间 2021-01-02 23:57
- 提问者网友:川水往事
- 2021-01-02 19:56
最佳答案
- 五星知识达人网友:独行浪子会拥风
- 2021-01-02 20:25
解:(x2+x+1)(x+2)
=x3+2x2+x2+2x+x+2
=x3+3x2+3x+2;
(x2-x-1)(x+1)
=x3+x2-x2-x-x-1
=x3-2x-1;
(x2+2x-1)(x-1)
=x3-x2+2x2-2x-x+1
=x3+x2-3x+1;
(x2-2x+3)(x-2)
=x3-2x2-2x2+4x+3x-6
=x3-4x2+7x-6;
(a2+3a-2)(a+3)
=a3+3a2+3a2+9a-2a-6
=a3+6a2+7a-6;
(a2-3a+4)(a-3)
=a3-3a2-3a2+9a+4a-12
=a3-6a2+13a-12;
(a2+4a+1)(2a-1)
=2a3-a2+8a2-4a+2a-1
=2a3+7a2-2a-1;
(a2-4a+2)(3a+2)
=3a3+2a2-12a2-8a+6a+4
=3a3-10a2-2a+4;
(2x2-3)(x+5)
=2x3+10x2-3x-15.解析分析:根据多项式乘以多项式的法则:多项式与多项式相乘,先用一个多项式的每一项乘另外一个多项式的每一项,再把所得的积相加,即(a+b)(m+n)=am+an+bm+bn,计算即可.点评:本题主要考查多项式乘以多项式的法则.注意不要漏项,漏字母,有同类项的合并同类项.
=x3+2x2+x2+2x+x+2
=x3+3x2+3x+2;
(x2-x-1)(x+1)
=x3+x2-x2-x-x-1
=x3-2x-1;
(x2+2x-1)(x-1)
=x3-x2+2x2-2x-x+1
=x3+x2-3x+1;
(x2-2x+3)(x-2)
=x3-2x2-2x2+4x+3x-6
=x3-4x2+7x-6;
(a2+3a-2)(a+3)
=a3+3a2+3a2+9a-2a-6
=a3+6a2+7a-6;
(a2-3a+4)(a-3)
=a3-3a2-3a2+9a+4a-12
=a3-6a2+13a-12;
(a2+4a+1)(2a-1)
=2a3-a2+8a2-4a+2a-1
=2a3+7a2-2a-1;
(a2-4a+2)(3a+2)
=3a3+2a2-12a2-8a+6a+4
=3a3-10a2-2a+4;
(2x2-3)(x+5)
=2x3+10x2-3x-15.解析分析:根据多项式乘以多项式的法则:多项式与多项式相乘,先用一个多项式的每一项乘另外一个多项式的每一项,再把所得的积相加,即(a+b)(m+n)=am+an+bm+bn,计算即可.点评:本题主要考查多项式乘以多项式的法则.注意不要漏项,漏字母,有同类项的合并同类项.
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- 1楼网友:不甚了了
- 2021-01-02 21:16
这下我知道了
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