C++编程，如何解决成员函数的二义性

不修改主程序，通过重定义成员函数Show的方法解决名字冲突

#include <iostream.h>
class Base1{
protected:
int m;
public:
void Show(){cout<<m<<endl;}
};
class Base2{
protected:
int n;
public:
void Show(){cout<<n<<endl;}
};
class Derived:public Base1,public Base2{
public:
void Set(int x,int y){m=x;n=y;}
};
void main(){
Derived Obj;
Obj.Set(45,87);
Obj.Show();
Obj.Base1::Show();
Obj.Base2::Show();
}

在Derived类中public中加入
void Show(){cout<<"sdf"<<endl;}
就可以实现对基类1，和基类2的同名函数的覆盖！
完整代码如下：
#include <iostream.h>
class Base1{
protected:
int m;
public:
void Show(){cout<<m<<endl;}
};
class Base2{
protected:
int n;
public:
void Show(){cout<<n<<endl;}
};
class Derived:public Base1,public Base2
{
public:
void Show(){cout<<"sdf"<<endl;} //加在这里！！！！！！！！！！！
void Set(int x,int y){m=x;n=y;}
};
void main(){
Derived Obj;
Obj.Set(45,87);
Obj.Show();
Obj.Base1::Show();
Obj.Base2::Show();
}