C程序求两数间的水仙花数问题。求正确答案。。说出怎么改。。谢谢！

#include"stdio.h"
main()
{
int m,n,a,x,y,z,d=0;
while(scanf("%d%d",&m,&n)!=EOF)
if(m >= 100 && m <= n && n<=999)
{
for(a=m;a<n;a++)
x=a/100;
y=a/10%10;
z=a%10;
if(a == x * x * x + y * y * y + z * z * z )
printf("%d",a);
d++;
}
if(d==0)
printf("no");
}

已改，楼主要运用好括号啊
#include <stdio.h>
void main()
{
int m,n,a,x,y,z,d=0;
while(scanf("%d%d",&m,&n)!=EOF)
{
d = 0; //把d每次都先赋值0
if(m >= 100 && m <= n && n<=999)
{
for (a = m; a <= n; a++) //for要括号括住多个语句
{
x=a/100;
y=a/10%10;
z=a%10;
if(a == x * x * x + y * y * y + z * z * z )
printf("%d ",a);
d++;
}
}
if(d==0)
printf("no");
printf("\n");
}
}

#include"stdio.h" main() { int m,n,a,x,y,z,d=0; scanf("%d%d",&m,&n); if(m >= 100 && m <= n && n<=999) { for(a=m;a<n;a++) { x=a/100; y=a/10%10; z=a%10; if(a == x * x * x + y * y * y + z * z * z ) printf("%d",a); d++; } } if(d==0) printf("no"); } 你思路是对的... 自己把自己写乱了...去了点东西就好了

#include <iostream> #include <cstdlib> using namespace std; inline int cube ( const int n ){ return n * n * n;} bool isnarcissistic ( const int n ){  int hundreds = n / 100;  int tens = n / 10 - hundreds * 10;  int ones = n % 10;  return cube(hundreds) + cube(tens) + cube(ones) == n; } int main(){  int sum = 0 ; for ( int i = 1; i < 10000; ++ i ){  if ( isnarcissistic(i) )  { cout << i <<" " ; sum += i ; } } cout << "\nsum = " << sum << endl ; return exit_success; }