帮忙，计算奥数一题，要过程，谢谢
答案:3 悬赏:80 手机版
解决时间 2021-07-30 06:38
- 提问者网友：半生酒醒
- 2021-07-30 00:11
帮忙，计算奥数一题，要过程，谢谢
最佳答案
- 五星知识达人网友：街头电车
- 2021-07-30 00:21
(1-1/2+1/3-1/4+...+1/99-1/100)/[1/(1+101)+1/(2+102)+1/(3+103)+...+1/(50+150)]
=(1+1/3+..+1/99-1/2-1/4-...-1/100)/(1/102+1/104+..+1/200)
=[1+1/2+..+1/100-2(1/2+1/4+..+1/100)]/[1/2(1/51+..+1/100)]
=[1+1/2+..+1/100-(1/1+1/2+..+1/50)]/[1/2(1/51+..+1/100)]
=(1/51+..+1/100)/[1/2(1/51+..+1/100)]
=2
=(1+1/3+..+1/99-1/2-1/4-...-1/100)/(1/102+1/104+..+1/200)
=[1+1/2+..+1/100-2(1/2+1/4+..+1/100)]/[1/2(1/51+..+1/100)]
=[1+1/2+..+1/100-(1/1+1/2+..+1/50)]/[1/2(1/51+..+1/100)]
=(1/51+..+1/100)/[1/2(1/51+..+1/100)]
=2
全部回答
- 1楼网友：逐風
- 2021-07-30 01:36
如此easy的问题，自己好好思考吧
- 2楼网友：你哪知我潦倒为你
- 2021-07-30 01:25
(1-1/2+1/3-1/4+...+1/99-1/100)/[1/(1+101)+1/(2+102)+1/(3+103)+...+1/(50+150)]
=(1+1/3+..+1/99-1/2-1/4-...-1/100)/(1/102+1/104+..+1/200)
=[1+1/2+..+1/100-2(1/2+1/4+..+1/100)]/[1/2(1/51+..+1/100)]
=[1+1/2+..+1/100-(1/1+1/2+..+1/50)]/[1/2(1/51+..+1/100)]
=(1/51+..+1/100)/[1/2(1/51+..+1/100)]
=2
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