哪个C++很强的？

有什么C程序不会做。

｛.对字符数组c1赋 '0'～'9'，
对字符数组c2赋 'A'～'Z'，然后输出c1和c2数组中的数据.｝

请个高手帮个忙

char c1[10] = "0123456789";

char c2[26] = "ABC.......XYZ";

printf("%s\n%s\n", c1, c2);

或者

char c1[10] = {0};

char c2[26] = {0};

int i = 0;

for (i = 0; i < 10; i++)

c1[i] = '0' + i;

for (i = 0; i < 26; i++)

c2[i] = 'A' + i;

printf(...);

char c1[9],c2[26];

for (i = 0; i < 10; i++)

c1[i] = '0' + i;

for (i = 0; i < 26; i++)

c2[i]='A'+i;

for (i = 0; i < 10; i++)

cout<<c1[i]<<" ";

cout<<endl;

for (i = 0; i < 26; i++)

cout<<c2[i]<<" ";

#include<iostream.h> void main() { int i,j; int c1[11]; char c2[27]; cout<<"c1={"; for(i=0;i<9;i++) { c1[i]=i; c1[i+1]=c1[i]+1; cout<<c1[i]<<" "; } cout<<c1[i]<<"}"<<endl; cout<<"c2={"; c2[0]=65; for(j=0;j<25;j++) { c2[j+1]=c2[j]+1; cout<<"'"<<c2[j]<<"'"<<","; } cout<<"'"<<c2[j]<<"'"<<"}"<<endl; }

这是什么问题，　

void set_array(char *A[], char char_begin, char char_end) // 假设数组Ａ足够大，　

{

　　while(char_begin <= char_end)

*A++ = begin++;

*A = '\0'; // make it to c character string ;

}

int main()

{

char a[50], b[50];

set_array(a, '0', '9');

set_array(b, 'A', 'Z');

printf("%s\t%s", a, b);

return 0;

}

下面写一个更简单方便的；依赖于expand(char A[], int size);

void expand(char *s)

{ char c;

char *temp = (char*)malloc(sizeof(char) * size); // to store the expanded string;

while((c = *s++) != '\0')

{

if(*s == '-' && *(s+ 1) >= c) // we need to expand

{

while(c <= *++s)

*tmep++ = c++;

}

else

*temp++ = c;

}

*temp = '\0';

strcpy(s, temp); // copy back to s;

free(temp);

}

下面可以这样写，　

#include <stdio.h>

#include <string.h>

int main()

{

char a[30] = "0-9"; // not chara[30] = "0123....9";

char b[30] = "A-Z"; // not char b[30] = "ABC....Z";

expand(a, 30);

expand(b, 30);

cout << a << "\t" << b;

return 0;

}