十字相乘，求解答！ （b²-5b）²-2（b²-5b）-24 a的4次方-8a²（a-1）+16（a-1）²
答案:1 悬赏:20 手机版
解决时间 2021-11-16 22:35
- 提问者网友：雾里闻花香
- 2021-11-16 08:40
十字相乘，求解答！ （b²-5b）²-2（b²-5b）-24 a的4次方-8a²（a-1）+16（a-1）²
最佳答案
- 五星知识达人网友：老鼠爱大米
- 2021-11-16 09:43
解
(m²-3m)-14(m²-3m)+40
=[(m²-3m)-10][(m²-3m)-4]
=(m²-3m-10)(m²-3m-4)
=(m-5)(m+2)(m-4)(m+1)
(b²-5b)²-10(b²-5b)-56
=[(b²-5b)-14][(b²-5b)+4]
=(b²-5b-14)(b²-5b+4)
=(b-7)(b+2)(b-4)(b-1)
(b²-5b)²-2(b²-5b)-24
=[(b²-5b)-6][(b²-5b)+4]
=(b²-5b-6)(b²-5b+4)
=(b-6)(a+1)(a-4)(a-1)
a^4-8a²(a-1)+16(a-1)²
=[a²-4(a-1)]²
=(a²-4a+4)²
=[(a-2)²]²
=(a-2)^4
(m²-3m)-14(m²-3m)+40
=[(m²-3m)-10][(m²-3m)-4]
=(m²-3m-10)(m²-3m-4)
=(m-5)(m+2)(m-4)(m+1)
(b²-5b)²-10(b²-5b)-56
=[(b²-5b)-14][(b²-5b)+4]
=(b²-5b-14)(b²-5b+4)
=(b-7)(b+2)(b-4)(b-1)
(b²-5b)²-2(b²-5b)-24
=[(b²-5b)-6][(b²-5b)+4]
=(b²-5b-6)(b²-5b+4)
=(b-6)(a+1)(a-4)(a-1)
a^4-8a²(a-1)+16(a-1)²
=[a²-4(a-1)]²
=(a²-4a+4)²
=[(a-2)²]²
=(a-2)^4
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