设计一个简单的计算器,完成两个数的加、减、乘、除。用select case实现,用if语句改写此题。
答案:2 悬赏:50 手机版
解决时间 2021-02-04 10:51
- 提问者网友:那叫心脏的地方装的都是你
- 2021-02-04 04:23
求=的代码
最佳答案
- 五星知识达人网友:人類模型
- 2021-02-04 05:15
Private Function asmdOperator(ByVal a As Integer, ByVal b As Integer, ByVal operator1 As Char) As Integer
Select Case operator1
Case "+"
Return a + b
Case "-"
Return a - b
Case "*"
Return a * b
Case "/"
Return a / b
Case Else
Throw New ApplicationException("错误的运算符")
End Select
End Function
Private Function asmdOperator2(ByVal a As Integer, ByVal b As Integer, ByVal operator1 As Char) As Integer
If operator1 = "+" Then
Return a + b
ElseIf operator1 = "-" Then
Return a - b
ElseIf operator1 = "*" Then
Return a * b
ElseIf operator1 = "/" Then
Return a / b
Else
Throw New ApplicationException("错误的运算符")
End If
End Function
Select Case operator1
Case "+"
Return a + b
Case "-"
Return a - b
Case "*"
Return a * b
Case "/"
Return a / b
Case Else
Throw New ApplicationException("错误的运算符")
End Select
End Function
Private Function asmdOperator2(ByVal a As Integer, ByVal b As Integer, ByVal operator1 As Char) As Integer
If operator1 = "+" Then
Return a + b
ElseIf operator1 = "-" Then
Return a - b
ElseIf operator1 = "*" Then
Return a * b
ElseIf operator1 = "/" Then
Return a / b
Else
Throw New ApplicationException("错误的运算符")
End If
End Function
全部回答
- 1楼网友:归鹤鸣
- 2021-02-04 06:24
你说呢...
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