fun1(int a,int b)
{
int c;
a+=a;b+=b;
c=fun2(a,b);
return c*c;
}
fun2(int a,int b)
{int c;
c=a*b%7;
return c;
}
main()
{int x=19,y=27;
printf("%d\n",fun1(x,y));
}
fun1(int a,int b)
{
int c;
a+=a;b+=b;
c=fun2(a,b);
return c*c;
}
fun2(int a,int b)
{int c;
c=a*b%7;
return c;
}
main()
{int x=19,y=27;
printf("%d\n",fun1(x,y));
}
函数fun2()的作用是:求ab积对7的余数
函数fun1()的作用是:借助fun2()求a的2倍与b的2倍的积除7的余数,返回c的平方
嘻嘻,懂了不??不懂加我870662874