高一简单的三角函数化简 （正弦sin与余弦cos之间的化简）机器语言表示：y=5*[sin（x)]^

高一简单的三角函数化简 （正弦sin与余弦cos之间的化简）机器语言表示：y=5*[sin（x)]^

y=5*[sin（x)]^2+[3^(1/2)]*[sin(x)]*[cos(x)]+6*[cos(x)]^2=5 + 2分之根号3*sin2x + (cosx)^2=5 + 2分之根号3*sin2x + (cos2x+1)/2=2分之根号3*sin2x + 二分之一cos2x + 5.5=sin(2x+π/6) + 5.5======以下答案可供参考======供参考答案1:y=y=5*[sin（x)]^2+[3^(1/2)]*[sin(x)]*[cos(x)]+6*[cos(x)]^2=5*[sin（x)]^2+6*[cos(x)]^2 +[3^(1/2)]*[sin(x)]*[cos(x)]+6*[cos(x)]^2=5*[sin（x)]^2+5*[cos(x)]^2 +[cos(x)]^2 +[3^(1/2)]*[sin(x)]*[cos(x)]+6*[cos(x)]^2=5*“【sin（x)]^2+[cos(x)]^2 】 +[cos(x)]^2 +[3^(1/2)]*[sin(x)]*[cos(x)]+6*[cos(x)]^2=5 +[cos(x)]^2 +[3^(1/2)]*[sin(x)]*[cos(x)]+6*[cos(x)]^2=5 +1/2[1+cos(2x)] +√3/2*[sin(2x)]=5.5 +1/2cos(2x) +√3/2*[sin(2x)]=5.5 +sin(π/6)cos(2x) + cos(π/6)*[sin(2x)]=5.5+sin(2x+π/6)供参考答案2:原始=5*[sin（x)]^2+3^(1/2)]*/2sin(2x)+6*[cos(x)]^2 =5+[cos(x)]^2+3^(1/2)]*/2sin(2x) =5.5+3^(1/2)]*/2sin(2x)+1/2cos(2x) =5.5+sin(2x+π/6)供参考答案3:y=5(sinx)^2+6(cosx)^2+根号3*sinx*cosx=5+(cosx)^2+根号3/2*2sinx*cosx=5+1/2*(1-sin(2x))+根号3/2*sin(2x)=5.5+根号3/2*sin(2x)-1/2*sin(2x)=5.5+sin(2x+a)又有a=arctan((1/2)/(根号3/2))=arctan(根号3/3)所以a=pi/6

哦，回答的不错