x+2/(x-4)(x-3),-2x/(4-x)(3-x) 通分
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解决时间 2021-01-15 02:38
- 提问者网友：爱了却不能说
- 2021-01-14 03:46
x+2/(x-4)(x-3),-2x/(4-x)(3-x) 通分
最佳答案
- 五星知识达人网友：街头电车
- 2021-01-14 05:17
x+2/(x-4)(x-3)=A/(x-4)+B/(x-3)
A+B=2
-3A-4B=2
(1)*3+(2)
B=-8
A=10
则x+2/(x-4)(x-3)=10/(x-4)-8/(x-3)
-2x/(4-x)(3-x) =A/(4-x)+B/(3-x)
3A+4B=0
A+B=2
(1)-(2)*3
B=-6
A=8
则-2x/(4-x)(3-x) =8/(4-x)-6/(3-x)追问0 0····那个是逗号、、不是一个相减的式子·········x+2/(x-4)(x-3）和 -2x/(4-x)(3-x) 通分……orz追答x+2/(x-4)(x-3)-2x/(4-x)(3-x)
=x+2/(x-4)(x-3)-2x/(x-4)(x-3)
=（x+2-2x)/(x-4)(x-3)
==（2-x)/(x-4)(x-3)
A+B=2
-3A-4B=2
(1)*3+(2)
B=-8
A=10
则x+2/(x-4)(x-3)=10/(x-4)-8/(x-3)
-2x/(4-x)(3-x) =A/(4-x)+B/(3-x)
3A+4B=0
A+B=2
(1)-(2)*3
B=-6
A=8
则-2x/(4-x)(3-x) =8/(4-x)-6/(3-x)追问0 0····那个是逗号、、不是一个相减的式子·········x+2/(x-4)(x-3）和 -2x/(4-x)(3-x) 通分……orz追答x+2/(x-4)(x-3)-2x/(4-x)(3-x)
=x+2/(x-4)(x-3)-2x/(x-4)(x-3)
=（x+2-2x)/(x-4)(x-3)
==（2-x)/(x-4)(x-3)
全部回答
- 1楼网友：夜风逐马
- 2021-01-14 05:41
x+2/(x-4)(x-3) -2x/(4-x)(3-x)
=x+2/(x-4)(x-3) -2x/(x-4)(x-3)
=（x+2-2x) /(x-4)(x-3)
==（2-x)/ (x-4)(x-3)
=x+2/(x-4)(x-3) -2x/(x-4)(x-3)
=（x+2-2x) /(x-4)(x-3)
==（2-x)/ (x-4)(x-3)
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