1/(x-2)+1/(x-8)=1/(x-4)+1/(x-6)
答案:1 悬赏:40 手机版
解决时间 2021-01-29 04:24
- 提问者网友：温旧梦泪无声
- 2021-01-28 11:07
1/(x-2)+1/(x-8)=1/(x-4)+1/(x-6)
最佳答案
- 五星知识达人网友：長槍戰八方
- 2021-01-28 12:14
1/(x-2)+1/(x-8)=1/(x-4)+1/(x-6)
1/(x-2)-1/(x-4)=1/(x-6)-1/(x-8)
(x-4-x+2)/[(x-2)(x-4)] = (x-8-x+6)/[(x-6)(x-8)]
-2/(x²-6x+8)=-2/(x²-14x+48)
x²-6x+8=x²-14x+48
8x=40
x=5
1/(x-2)-1/(x-4)=1/(x-6)-1/(x-8)
(x-4-x+2)/[(x-2)(x-4)] = (x-8-x+6)/[(x-6)(x-8)]
-2/(x²-6x+8)=-2/(x²-14x+48)
x²-6x+8=x²-14x+48
8x=40
x=5
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