设an为等比数列，bn=log2an为等差数列，（2为底数），Tn为bn的前n项和，且t6=64，

设an为等比数列，bn=log2an为等差数列，（2为底数），Tn为bn的前n项和，且t6=64，

如图


追问不好意思哦，我算出来也是这个可是我老师说不对，他让我多想想2333追答是这个。除非你题目给错了。我想不出来还有别的追问那好吧谢谢啦，麻烦了

数列{an}是等比数列，an=a1qⁿ⁻¹，log2(an)有意义，a1>0，q>0
bn=log2(an)=log2(a1qⁿ⁻¹)=log2(a1)+(n-1)log2(q)
T6=6log2(a1)+(0+1+...+5)log2(q)
=6log2(a1)+15log2(q)
=log2(a1⁶q¹⁵)
=log2[(a1q²·a1q³)³]
=log2[(a3a4)³]
=64
=2⁶
a3a4=2²=4
a3a4的值为4追问诶这个最后把3除过去后，log到哪去了啊？追答数列{an}是等比数列，an=a1qⁿ⁻¹，log2(an)有意义，a1>0，q>0
bn=log2(an)=log2(a1qⁿ⁻¹)=log2(a1)+(n-1)log2(q)
T6=6log2(a1)+(0+1+...+5)log2(q)
=6log2(a1)+15log2(q)
=log2(a1⁶q¹⁵)
=log2[(a1q²·a1q³)³]
=log2[(a3a4)³]
=3log2(a3a4)
=64
log2(a3a4)=64/3
a3a4=2^(64/3)