（0.1²+0.2²+0.3²+0.4²）²/（0.1³+0.2³+0.3³+0.4³）³
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解决时间 2021-03-31 23:39
- 提问者网友：沦陷
- 2021-03-31 10:51
（0.1²+0.2²+0.3²+0.4²）²/（0.1³+0.2³+0.3³+0.4³）³
最佳答案
- 五星知识达人网友：往事埋风中
- 2021-03-31 12:03
（0.1^2+0.2^2+0.3^2+0.4^2)^2÷(0.1^3+0.2^3+0.3^3+0.4^3）^3
=[(1/10)^2+(2/10)^2+(3/10)^2+(4/10)^2]^2÷[(1/10)^3+(2/10)^3+(3/10)^3+(4/10)^3]^3
=[(1+4+9+16)/100]^2÷[(1+8+27+64)/1000]^3
=(20/100)^2÷(100/1000)^3
=(1/5)^2÷(1/10)^3
=1/25÷1/1000
=1000/25
=40
=[(1/10)^2+(2/10)^2+(3/10)^2+(4/10)^2]^2÷[(1/10)^3+(2/10)^3+(3/10)^3+(4/10)^3]^3
=[(1+4+9+16)/100]^2÷[(1+8+27+64)/1000]^3
=(20/100)^2÷(100/1000)^3
=(1/5)^2÷(1/10)^3
=1/25÷1/1000
=1000/25
=40
全部回答
- 1楼网友：轻雾山林
- 2021-03-31 13:14
（0.1^2+0.2^2+0.3^2+0.4^2)^2÷(0.1^3+0.2^3+0.3^3+0.4^3）^3
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