(1)log3(底数)4(底数)=
(2)log2(底数)12 (底数)=
(1)log3(底数)4(底数)=
(2)log2(底数)12 (底数)=
(1)2a/b
(2)2+(b/a)
(1)log3(底数)4 =2log3(底数)2 =2lg2/lg3 =2a/b
(2)log2(底数)12 =log2(底数)4+log2(2为底数)3 =2+log2(底数)3 =2+lg3/lg2 =2+b/a
1、b/2a
2、a/2a+b
1.原式=lg4/lg3=2lg2/lg3=2a/3
2.原式=lg2/(lg3*2lg2)=a/(b*2a)=1/2b
1,log3 4=lg4/lg3=2lg2/lg3=2a/b
2,log2 12=lg12/lg2=lg3+lg4/lg2=b+2a/a