一些关于几何原本的问题1.命题II.5的内容是什么(要给出证明的哦)2.命题VI.23的内容和证明
答案:2 悬赏:50 手机版
解决时间 2021-02-09 21:06
- 提问者网友:斑駁影
- 2021-02-09 00:32
一些关于几何原本的问题1.命题II.5的内容是什么(要给出证明的哦)2.命题VI.23的内容和证明
最佳答案
- 五星知识达人网友:北城痞子
- 2021-02-09 01:05
BOOK II Proposition 5If a straight line is cut into equal and unequal segments,then the rectangle contained by the unequal segments of the whole together with the square on the straight line between the points of section equals the square on the half.用代数的语言,xy={(x+y)/2}^2-{(x-y)/2}^2.BOOK VIProposition 23Equiangular parallelograms have to one another the ratio compounded of the ratios of their sides.这是关于平行四边形面积的.This proposition is a generalization of the basic formula for the area of a rectangle,that is,the area of a rectangle is the product of its length and width.Such a formula depends on predetermined units of length and area so that the unit area is the area of a square whose sides have length equal to the unit length.Euclid and other Greek mathematicians did not use predetermined units of length or area,so they expressed this formula as a proportion.We would state that proportion as saying the ratio of the area of a given rectangle to the area of a given square is the product of the ratios of the lengths of the sides of the rectangle to the length of a side of the square.Of course,Euclid would say that without using the words 'area' and 'length' as follows:the ratio of the a given rectangle to a given square is the product of the ratios of the sides of the rectangle to a side of the square.Note that his terminology for a product of ratios involves compounding the ratios. A natural generalization of the ratio of a rectangle to a square is the ratio of a rectangle to a rectangle.A broader generalization is the ratio of one parallelogram to another parallelogram having the same angles.That gives the generalization as stated in this proposition.
全部回答
- 1楼网友:舍身薄凉客
- 2021-02-09 01:54
对的,就是这个意思
我要举报
如以上问答信息为低俗、色情、不良、暴力、侵权、涉及违法等信息,可以点下面链接进行举报!
大家都在看
推荐资讯