关于JAVA的问题急啊

创建一个可以保存10个数字的数组。程序运行后，从键盘输入10个任意数字，实现以下功能，输出如下图：

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您输入的10个数字分别是：

12 4 23 4 11 33 22 14 3 2

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小于等于10的数字有 4 个

小于等于10的数字的平均值是 3.25

大于10的数字的平均值是 19.2

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谁能帮忙解决一下

public class Test {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int[] array = new int[10];
for (int i = 0; i < array.length; i++) {
System.out.print("请输入第" + (i + 1) + "个数：");
array[i] = input.nextInt();
}
int sumOfLess = 0, sumOfLarger = 0;
int countOfLess = 0, countOfLarger = 0;
System.out.print("你输入的数分别是：");
for (int i = 0; i < array.length; i++) {
System.out.print(array[i] + " ");
if (array[i] <= 10) {
countOfLess++;
sumOfLess += array[i];
} else {
countOfLarger++;
sumOfLarger += array[i];
}
}
System.out.println("小于等于10的数字有" + countOfLess + "个！");
System.out.println("小于等于10的数字的平均值是"
+ ((double) sumOfLess / countOfLess));
System.out.println("大于10的数字有" + countOfLarger + "个！");
System.out.println("大于10的数字的平均值是"
+ ((double) sumOfLarger / countOfLarger));
}
}

哎！太难了！爱莫能助啊

import java.util.*;

public class Test {

public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int[] a = new int[10]; for (int i = 0; i < a.length; ++i) { a[i] = scanner.nextInt(); } int le = 0, gt = 0, sumle = 0, sumgt = 0; for (int i = 0; i < a.length; ++i) { if (a[i] <= 10) { ++le; sumle += a[i]; } else { ++gt; sumgt += a[i]; } }

System.out.printf("小于等于10的数字有 %d个\n", le); System.out.printf("小于等于10的平均值是 %.2f\n", ((double) sumle) / ((double) le)); System.out.printf("大于10的平均值是 %.2f\n", ((double) sumgt) / ((double) gt)); } }