C语言编程求西西弗斯串

C语言编程求西西弗斯串

我花了好久，你一分不给，让我情何以堪啊


#include
#include

#define ARRAY_LEN 100
char *iToStr(char *s, int value, int *num)
{
int i = 0;
int modtmp = 0;
int tmp = value;
int j = 0;
char ctmp = '0';

*num = 0;
while (0 != tmp)
{
modtmp = tmp % 10;
s[i++] = modtmp + '0';
tmp = tmp / 10;
}

s[i] = '\0';
for (j = 0; j < i/2; j++)
{
ctmp = s[j];
s[j] = s[i-j-1];
s[i-j-1] = ctmp;
}

*num = i;
return s;}
char* fun(char a[]){
char *pTmp = a;

int oddNum = 0; //奇数个数 int evenNum = 0; //偶数个数
int totalNum = 0;

int i = 0;
char cstr[20] = {0}; char *pcstr = cstr;
int cnum = 0;

int tmp = 0;
for (; *pTmp != '\0'; ++pTmp)
{
tmp = *pTmp - '0';
if (0 <= tmp && tmp <= 9)
{
if(tmp % 2 == 0)
{
evenNum++;
}
else
{
oddNum++;
}
totalNum++;
}
else
{
break;//遇到不是数字的字符了
}
}

iToStr(pcstr, evenNum, &cnum);
pcstr = pcstr+cnum;
iToStr(pcstr, oddNum, &cnum);
pcstr = pcstr+cnum;
iToStr(pcstr, totalNum, &cnum);

printf("%s \n", cstr);
if (0 == strcmp(a, cstr)) {

memcpy(a, cstr, strlen(cstr));
a[strlen(cstr)] = '\0';
return a;
}
else
{
return fun(cstr);
}
}

void main(){
char a[ARRAY_LEN];
printf("请输入一个数字串: ");
int b = 0;
fgets(a, ARRAY_LEN, stdin); //这样不会照成溢出

printf("神秘的数是:%s\n",fun(a));}

神秘数　不就是123吗　　gets函数好像取得是字符串吧　而你要操作的数据是整数　类型不同