三台机械发生故障的几率为0.1,0.2,0.3，求两台机械发生故障的概率？
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解决时间 2021-11-09 08:18
- 提问者网友：黑米和小志
- 2021-11-09 03:04
三台机械发生故障的几率为0.1,0.2,0.3，求两台机械发生故障的概率？
最佳答案
- 五星知识达人网友：妄饮晩冬酒
- 2021-11-09 03:39
恰有两台机械发生故障的概率:
0.1*(0.2*(1-0.3)+(1-0.2)*0.3)+(1-0.1)*0.2*0.3
=0.1*(0.2*0.7+0.8*0.3)+0.9*0.2*0.3
=0.1*0.38+0.054
=0.092
恰有两台机械发生故障的概率:
0.1*0.2*(1-0.3)+0.1*(1-0.2)*0.3+(1-0.1)*0.2*0.3
=0.1*0.2*0.7+0.1*0.8*0.3+0.9*0.2*0.3
=0.014+0.024+0.054
=0.092
0.1*(0.2*(1-0.3)+(1-0.2)*0.3)+(1-0.1)*0.2*0.3
=0.1*(0.2*0.7+0.8*0.3)+0.9*0.2*0.3
=0.1*0.38+0.054
=0.092
恰有两台机械发生故障的概率:
0.1*0.2*(1-0.3)+0.1*(1-0.2)*0.3+(1-0.1)*0.2*0.3
=0.1*0.2*0.7+0.1*0.8*0.3+0.9*0.2*0.3
=0.014+0.024+0.054
=0.092
全部回答
- 1楼网友：逐風
- 2021-11-09 04:06
恰有两台机械发生故障的概率:
0.1*(0.2*(1-0.3)+(1-0.2)*0.3)+(1-0.1)*0.2*0.3
=0.1*(0.2*0.7+0.8*0.3)+0.9*0.2*0.3
=0.1*0.38+0.054
=0.092
恰有两台机械发生故障的概率:
0.1*0.2*(1-0.3)+0.1*(1-0.2)*0.3+(1-0.1)*0.2*0.3
=0.1*0.2*0.7+0.1*0.8*0.3+0.9*0.2*0.3
=0.014+0.024+0.054
=0.092
0.1*(0.2*(1-0.3)+(1-0.2)*0.3)+(1-0.1)*0.2*0.3
=0.1*(0.2*0.7+0.8*0.3)+0.9*0.2*0.3
=0.1*0.38+0.054
=0.092
恰有两台机械发生故障的概率:
0.1*0.2*(1-0.3)+0.1*(1-0.2)*0.3+(1-0.1)*0.2*0.3
=0.1*0.2*0.7+0.1*0.8*0.3+0.9*0.2*0.3
=0.014+0.024+0.054
=0.092
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