c++怎么用<time.h>分别获取当前的年,月,日赋值于toyear tomonth today这3个变量中

c++怎么用<time.h>分别获取当前的年,月,日赋值于toyear tomonth today这3个变量中

#include
#include
#include
main()
{
time_t seconds;
struct tm * timeinfo;
int sec,toyear,tomonth,today;

seconds = time (NULL);
timeinfo = localtime ( &seconds );
toyear= timeinfo->tm_year + 1900;
tomonth= timeinfo->tm_mon + 1;
today = timeinfo->tm_mday;
printf(" %d %d %d\n",toyear,tomonth,today);

return 0;
}

Time t;
CString tt=t.GetLocaleTime();
Format一下就好了，因为一直用插件，具体怎么用记不清了