编程实现从键盘输入任意三个字符串,从中找出长度最大的一个并输出。

编程实现从键盘输入任意三个字符串,从中找出长度最大的一个并输出。

public class Test {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("输入第一个字符串：");
String str1 = sc.nextLine();
System.out.println("输入第二个字符串：");
String str2= sc.nextLine();
System.out.println("输入第三个字符串：");
String str3 = sc.nextLine();
if(str1.length()>str2.length()){
if(str1.length()>str3.length()){
System.out.println("str1最大:" + str1);
}else{
System.out.println("str3最大:" + str1);
}
}else{
if(str2.length()>str3.length()){
System.out.println("str2最大:" + str1);
}else{
System.out.println("str3最大:" + str1);
}
}
}
}

#include<stdio.h>

#define max(a,b) (a>b?a:b)

void main()

{

char str[1000];

char maxstr[1000];

int maxlen=0;

for(int i=0;i<3;i++)

{

scanf("%s",str);

if(maxlen<strlen(str))

{

maxlen=strlen(str);

strcpy(maxstr,str);

}

}

printf(maxstr);

}

这是我的一个7个字符数组的比较排序输出，你运行一下就明白了

Private Sub Command3_Click()

dim str(7)

str(0) = "ichi" str(1) = "Akita" str(2) = "Fukui" str(3) = "Fukuoka" str(4) = "Fukushima" str(5) = "Gifu" str(6) = "Kochi" str(7) = "Kumamoto" Dim arr As String Dim a(7) As String Dim temp As String Dim i As Integer

For i = 0 To 7

For j = 0 To 6 - i If (Len(str(j)) > Len(str(j + 1))) Then temp = str(j) str(j) = str(j + 1) str(j + 1) = temp End If Next j Next i For i = 0 To 7 print str(i) Next End Sub