分解因式1/7(x-y)^3+7(y-x)
答案:2 悬赏:40 手机版
解决时间 2021-04-03 18:01
- 提问者网友：练爱
- 2021-04-02 18:28
分解因式1/7(x-y)^3+7(y-x)
最佳答案
- 五星知识达人网友：爱难随人意
- 2021-04-02 20:04
解：
(1/7)(x-y)³+7(y-x)
=(1/7)(x-y)³-7(x-y)
=(1/7)(x-y)[(x-y)²-49]
=(1/7)(x-y)(x-y+7)(x-y-7)
(1/7)(x-y)³+7(y-x)
=(1/7)(x-y)³-7(x-y)
=(1/7)(x-y)[(x-y)²-49]
=(1/7)(x-y)(x-y+7)(x-y-7)
全部回答
- 1楼网友：底特律间谍
- 2021-04-02 20:59
1/7（x-y）³+7(y-x)
=1/7(x-y)³-7(x-y)
=1/7(x-y)(x²+y²-2xy-49)
=1/7(x-y)[(x-y)²-7²]
=1/7(x-y)(x-y+7)(x-y-7)
=1/7(x-y)³-7(x-y)
=1/7(x-y)(x²+y²-2xy-49)
=1/7(x-y)[(x-y)²-7²]
=1/7(x-y)(x-y+7)(x-y-7)
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