tan(派/4+a)=1/2,tan(b-派/4)=1/3则tan(a+b)=?
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解决时间 2021-02-25 21:40
- 提问者网友：心如荒岛囚我终老
- 2021-02-24 21:30
tan(派/4+a)=1/2,tan(b-派/4)=1/3则tan(a+b)=?
最佳答案
- 五星知识达人网友：患得患失的劫
- 2021-02-24 22:48
tan(a+b)
=tan[(a+π/4)+(b-π/4)]
=[tan(a+π/4)+tan(b-π/4)]/[1-tan(a+π/4)tan(b-π/4)]
=(1/2+1/3)/(1-1/2*1/3)
=(5/6)/(5/6)
=1
=tan[(a+π/4)+(b-π/4)]
=[tan(a+π/4)+tan(b-π/4)]/[1-tan(a+π/4)tan(b-π/4)]
=(1/2+1/3)/(1-1/2*1/3)
=(5/6)/(5/6)
=1
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