编写一段程序,求两个整数123和456的和,差,积与商,并输出结果c语言

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解决时间 2021-04-04 03:38

提问者网友：疯孩纸
2021-04-03 18:06

最佳答案

五星知识达人网友：笑迎怀羞
2021-04-03 19:19

#include
void main(){
int a=123,b=456;
double c=(double)a/b;
printf("a+b=%d\n",a+b);
printf("a-b=%d\n",a-b);
printf("a*b=%d\n",a*b);
printf("a/b=%lf\n",c);
}

全部回答

1楼网友：骨子里都是戏
2021-04-03 21:22

#include
void main(int argc, char *argv[])
{ int iNum1,iNum2;
printf("请输入二个数:\n");
scanf("%d %d",&iNum1,&iNum2);
printf("%d+%d=%d\n",iNum1,iNum2,iNum1+iNum2);
printf("%d-%d=%d\n",iNum1,iNum2,iNum1-iNum2);
printf("%d*%d=%d\n",iNum1,iNum2,iNum1*iNum2);
printf("%d/%d=%d\n",iNum1,iNum2,iNum1*iNum2);
}
只需要给iNum1和iNum2赋值为123和456，那么他们的和差积商就可以计算出来。

2楼网友：爱难随人意
2021-04-03 20:31

#include
int main(){
    float x = 123.0;
    float y = 456.0;
    int a = x + y;
    int h = x - y;
    int m = x * y;
    float di = x / y;
    printf ("addition: %d ",a);
    printf ("difference: %d ",h);
    printf ("multiplication: %d ",m);
    printf ("division: %f",di);
    return 0;
}

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