求AES加解／密码密软件程序！！！

求AES加解／密码密软件程序！！！

有界面，我这里有个，但是是c#语言的，你以为如何？
下面是c版本的
AES加密算法源代码
//AES.h

#define decrypt TRUE
#define encrypt FALSE
#define TYPE BOOL

typedef struct _AES{
int Nb;
int Nr;
int Nk;
unsigned long *Word;
unsigned long *State;
}AES;


void Cipher(
unsigned char* input,
int inSize,
unsigned char* out,
unsigned char* key,
int keySize);


void InvCipher(
unsigned char* input,
int inSize,
unsigned char* out,
unsigned char* key,
int keySize);


AES *InitAES(AES *aes,
int inSize,
unsigned char* key,
int keySize, TYPE type);


AES *InitAES(
int inSize,
unsigned char* key,
int keySize, BOOL );


void CipherLoop(
AES *aes);

void InvCipherLoop(
AES *aes);


void freeAES(
AES *aes);

//AES.cpp

#include "stdafx.h"
#include
#include
#include "AES.h"
unsigned char* SubWord(unsigned char* word);
unsigned long* keyExpansion(unsigned char* key, int Nk, int Nr,int);

void Cipher(unsigned char* input, int inSize, unsigned char* out, unsigned char* key, int keySize)
{
AES aes ;
InitAES(&aes,inSize,key,keySize,encrypt);

memcpy(aes.State,input,inSize);
CipherLoop(&aes);
memcpy(out,aes.State,inSize);

}


void InvCipher(unsigned char* input, int inSize, unsigned char* out, unsigned char* key, int keySize)
{
AES aes;
InitAES(&aes,inSize,key,keySize,decrypt);
memcpy(aes.State,input,inSize);
InvCipherLoop(&aes);
memcpy(aes.State,out,inSize);
}


AES *InitAES(AES *aes,int inSize, unsigned char *key, int keySize, TYPE type)
{
int Nb = inSize >>2,
Nk = keySize >>2,
Nr = Nb < Nk ? Nk:Nb+6;
aes->Nb = Nb;
aes->Nk = Nk;
aes->Nr = Nr;
aes->Word = keyExpansion(key,Nb,Nr,Nk);

aes->State = new unsigned long[Nb+3];
if(type)
aes->State += 3;
return aes;
}


AES *InitAES(int inSize, unsigned char* key, int keySize,unsigned long type)
{
return InitAES(new AES(),inSize,key,keySize,type);
}

void CipherLoop(AES *aes)
{
unsigned char temp[4];
unsigned long *word8 = aes->Word,
*State = aes->State;

int Nb = aes->Nb,
Nr = aes->Nr;

int r;
for (r = 0; r < Nb; ++r)
{
State[r] ^= word8[r];
}
for (int round =1; round {
word8 += Nb;

memcpy(State+Nb,State,12);

for(r =0; r {

temp[0] = Sbox[*((unsigned char*)State)];
temp[1] = Sbox[*((unsigned char*)(State+1)+1)];
temp[2] = Sbox[*((unsigned char*)(State+2)+2)];
temp[3] = Sbox[*((unsigned char*)(State+3)+3)];

*((unsigned char*)State) = Log_02[temp[0]] ^ Log_03[temp[1]] ^ temp[2] ^ temp[3];
*((unsigned char*)State+1) = Log_02[temp[1]] ^ Log_03[temp[2]] ^ temp[3] ^ temp[0];
*((unsigned char*)State+2) = Log_02[temp[2]] ^ Log_03[temp[3]] ^ temp[0] ^ temp[1];
*((unsigned char*)State+3) = Log_02[temp[3]] ^ Log_03[temp[0]] ^ temp[1] ^ temp[2];

*State ^= word8[r];
State++;
}
State -= Nb;
}

memcpy(State+Nb,State,12);

word8 += Nb;
for(r =0; r {
*((unsigned char*)State) = Sbox[*(unsigned char*)State];
*((unsigned char*)State+1) = Sbox[*((unsigned char*)(State+1)+1)];
*((unsigned char*)State+2) = Sbox[*((unsigned char*)(State+2)+2)];
*((unsigned char*)State+3) = Sbox[*((unsigned char*)(State+3)+3)];

*State ^= word8[r];
State++;
}
}

void InvCipherLoop(AES *aes)
{
unsigned long *Word = aes->Word,
*State = aes->State;

int Nb = aes->Nb,
Nr = aes->Nr;

unsigned char temp[4];

int r =0;
Word += Nb*Nr;
for (r = 0; r < Nb; ++r)
{
State[r] ^= Word[r];
}

State -= 3;

for (int round = Nr-1; round > 0; --round)
{

memcpy(State,State+Nb,12);


Word -= Nb;
State += Nb+2;

for(r = Nb-1; r >= 0; r--)
{

temp[0] = iSbox[*(byte*)State];
temp[1] = iSbox[*((byte*)(State-1)+1)];
temp[2] = iSbox[*((byte*)(State-2)+2)];
temp[3] = iSbox[*((byte*)(State-3)+3)];

*(unsigned long*)temp ^= Word[r];

*(unsigned char*)State = Log_0e[temp[0]] ^ Log_0b[temp[1]] ^ Log_0d[temp[2]] ^ Log_09[temp[3]];
*((unsigned char*)State+1) = Log_0e[temp[1]] ^ Log_0b[temp[2]] ^ Log_0d[temp[3]] ^ Log_09[temp[0]];
*((unsigned char*)State+2) = Log_0e[temp[2]] ^ Log_0b[temp[3]] ^ Log_0d[temp[0]] ^ Log_09[temp[1]];
*((unsigned char*)State+3) = Log_0e[temp[3]] ^ Log_0b[temp[0]] ^ Log_0d[temp[1]] ^ Log_09[temp[2]];

State --;
}
State -= 2;
}

Word -= Nb;
memcpy(State,State+Nb,12);

State += Nb+2;
for(r = Nb-1; r >= 0; r--)
{

*(unsigned char*)State = iSbox[*(unsigned char*)State];
*((unsigned char*)State+1) = iSbox[*((unsigned char*)(State-1)+1)];
*((unsigned char*)State+2) = iSbox[*((unsigned char*)(State-2)+2)];
*((unsigned char*)State+3) = iSbox[*((unsigned char*)(State-3)+3)];

*State ^= Word[r];
State --;
}
}

unsigned long* keyExpansion(byte* key, int Nb, int Nr, int Nk)
{
unsigned long *w =new unsigned long[Nb * (Nr+1)]; // 4 columns of bytes corresponds to a word

memcpy(w,key,Nk<<2);
unsigned long temp;

for (int c = Nk; c < Nb * (Nr+1); ++c)
{
//把上一轮的最后一行放入temp
temp = w[c-1];
//判断是不是每一轮密钥的第一行
if (c % Nk == 0)
{
//左旋8位
temp = (temp<<8)|(temp>>24);
//查Sbox表
SubWord((byte*)&temp);
temp ^= Rcon[c/Nk];
}
else if ( Nk > 6 && (c % Nk == 4) )
{
SubWord((byte*)&temp);
}
//w[c-Nk] 为上一轮密钥的第一行
w[c] = w[c-Nk] ^ temp;
}
return w;
}

unsigned char* SubWord(unsigned char* word)
{
word[0] = Sbox[ word[0] ];
word[1] = Sbox[ word[1] ];
word[2] = Sbox[ word[2] ];
word[3] = Sbox[ word[3] ];
return word;
}

void freeAES(AES *aes)
{
// for(int i=0;iNb;i++)
// {
// printf("%d\n",i);
// free(aes->State[i]);
// free(aes->Word[i]);
// }
// printf("sdffd");
}