如题
已知x+y=5xy,求(3x+xy+3y)/(x-2xy+y)
如题
已知x+y=5xy,求(3x+xy+3y)/(x-2xy+y)
(3x+xy+3y)/(x-2xy+y)
=[3(x+y)+xy]/(x+y-2xy)
=(3×5xy+xy)/(5xy-2xy)
=(16xy)/(3xy)
=16/3
原式=[3(x+y)+xy]/(x+y-2xy)
把x+y=5xy代入得
16xy/3xy=16/3
(3x+xy+3y)/(x-2xy+y)={3(x+y)+xy}/{(x+y)-2xy}=16xy/3xy=16/3