C#两个数组消除相同的数据

int[] zong = { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51 };

int[] zhong={0,0,0,21,4,0,5,0,6,0,2,0,0,0,0,0,0,0,0,0,0,}

zong这个数组去掉 zhong里面有的数据

int[] zong = { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
int[] zhong= { 0,4,5,6 };
List<int> result= new List<int>();
foreach(int a in zong)
{
if(!zhong.Contains(a))
result.Add(a);
}
zong=new int[result.Count]; //重新设置长度
result.CopyTo(zong); //将List结果复制到数组zong中；

再开一个数组，比如叫int[] result。对于zong中的每一个数，如果在zhong中出现，则不管；如果在zhong中没出现，就加入result。最后result就是你要的结果。伪码： foreach (int intFromZong in zong) { bool hasDuplicate = false; foreach (int intFromZhong in zhong) { if (intFromZong == intFromZhong) { hasDuplicate = true; break;} } if (!hasDuplicate) result.Add(intFromZong); }

参考我的类似代码：

如果你用的是vs2008或者以上版本，建议使用扩展方法封装一个list比较方法，快速可以比较出两个list之间有多少元素相同或者不同，比如：

using system;
using system.collections.generic;
using system.linq;
using system.text;

namespace consoleapplication1
{
    static class myextender
    {
    public static ienumerable<t> getdifferencecollection<t>(this list<t> collection, ilist<t> collection2) where t:icomparable<t>
    {
    list<t> result = new list<t>();

    foreach (t item in collection2)
    {
    if (collection.find(delegate(t i) { return i.compareto(item) == 0; }).compareto(item)!=0)
    {
    result.add(item);
    }
    }
    return result;
    }
    }

    class program
    {
    static void main(string[] args)
    {
    list<int> numbers = new list<int>() { 1, 2, 3 };
    list<int> numbers2 = new list<int>() {5, 1, 2, 3, 4 };

    var result = numbers.getdifferencecollection<int>(numbers2);

    foreach (var item in result)
    {
    console.writeline(item);
    }
    }
    }
}