java编写程序实现以下功能

（1）产生5000个1~9999之间的随机整数，并将其存入文本文件a.txt中。
（2）从文件中读取这五千个整数，并计算其最大值、最小值、平均值。

急——

public static void main(String[] args)
{
test();
}
public static void test()
{
String tempStr="";
for(int i=0;i<5000;i++)
{
double a=Math.random()*9999;
int aa=(int)a+1;
tempStr+=aa+"\r\n";
}
outputData("c:\\a.txt",tempStr);
test1();
}
public static void outputData(String filePath, String text)
{
try
{
BufferedWriter rw = new BufferedWriter(new OutputStreamWriter(
new FileOutputStream(filePath), "UTF-8"));
rw.write(text);
rw.close();
}
catch (Exception e)
{
e.printStackTrace();
}
}
public static void test1()
{
String s=new String();
int leng=0;
int test[]=new int[5000];
try
{
BufferedReader input = new BufferedReader(new FileReader("c:\\a.txt"));
while ((s = input.readLine()) != null&&leng<5000)
{
test[leng]=Integer.parseInt(s);
leng++;
}
input.close();
int max=test[0];
int min=test[0];
int sum=0;
for(int i=0;i<5000;i++)
{
if(test[i] min=test[i];
if(test[i]>max)
max=test[i];
sum+=test[i];
}
System.out.println("max="+max);
System.out.println("min="+min);
System.out.println("avg="+(double)sum/5000);
}
catch (Exception e)
{
e.printStackTrace();
}
}

public static void main(string[] args) { test(); } public static void test() { string tempstr=""; for(int i=0;i&lt;5000;i++) { double a=math.random()*9999; int aa=(int)a+1; tempstr+=aa+"\r\n"; } outputdata("c:\\a.txt",tempstr); test1(); } public static void outputdata(string filepath, string text) { try { bufferedwriter rw = new bufferedwriter(new outputstreamwriter( new fileoutputstream(filepath), "utf-8")); rw.write(text); rw.close(); } catch (exception e) { e.printstacktrace(); } } public static void test1() { string s=new string(); int leng=0; int test[]=new int[5000]; try { bufferedreader input = new bufferedreader(new filereader("c:\\a.txt")); while ((s = input.readline()) != null&amp;&amp;leng&lt;5000) { test[leng]=integer.parseint(s); leng++; } input.close(); int max=test[0]; int min=test[0]; int sum=0; for(int i=0;i&lt;5000;i++) { if(test[i]&lt;min) min=test[i]; if(test[i]&gt;max) max=test[i]; sum+=test[i]; } system.out.println("max="+max); system.out.println("min="+min); system.out.println("avg="+(double)sum/5000); } catch (exception e) { e.printstacktrace(); } }